H 60° Figure 6 G M 8. A uniform rod HG of length 2L m and mass m = 2 kg is hinged at end H, as shown in Figure 6 A mass Mg=100 N is hung at the other end G. A horizontal cable at the midpoint of the rod holds it at an angle of 60° to the horizontal. The cable is under a constant tension T. (a) Draw a diagram showing all the forces acting on the rod and determine the tension T in the cable. (b) Calculate both the x and y components (Fr and F₁) of the force F at the hinge H. (c) Will the net force F at H act along the rod HG? Justify your answer.

Principles of Physics: A Calculus-Based Text
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Chapter10: Rotational Motion
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H
60°
Figure 6
G
M
8. A uniform rod HG of length 2L m and mass m = 2 kg is hinged at end H, as shown in Figure 6
A mass Mg=100 N is hung at the other end G. A horizontal cable at the midpoint of the rod
holds it at an angle of 60° to the horizontal. The cable is under a constant tension T.
(a) Draw a diagram showing all the forces acting on the rod and determine the tension T in
the cable.
(b) Calculate both the x and y components (Fr and F₁) of the force F at the hinge H.
(c) Will the net force F at H act along the rod HG? Justify your answer.
Transcribed Image Text:H 60° Figure 6 G M 8. A uniform rod HG of length 2L m and mass m = 2 kg is hinged at end H, as shown in Figure 6 A mass Mg=100 N is hung at the other end G. A horizontal cable at the midpoint of the rod holds it at an angle of 60° to the horizontal. The cable is under a constant tension T. (a) Draw a diagram showing all the forces acting on the rod and determine the tension T in the cable. (b) Calculate both the x and y components (Fr and F₁) of the force F at the hinge H. (c) Will the net force F at H act along the rod HG? Justify your answer.
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