Given the following: Volume of K₂C204 = 0.01 L [K₂C204] = 0.025 M Volume of HCl added = 0.020 L [HCl] = 0.020 M Solve for the titration pH after adding the HCl (Note: Ka1 = 0.056 and Ka2 = 0.000054)

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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Given the following:
Volume of K₂C204 = 0.01 L
[K₂C204] = 0.025 M
Volume of HCl added = 0.020 L
[HCl] = 0.020 M
Solve for the titration pH after adding the HCl (Note: Ka1 = 0.056 and Ka2 = 0.000054)
Transcribed Image Text:Given the following: Volume of K₂C204 = 0.01 L [K₂C204] = 0.025 M Volume of HCl added = 0.020 L [HCl] = 0.020 M Solve for the titration pH after adding the HCl (Note: Ka1 = 0.056 and Ka2 = 0.000054)
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