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- Predict whether A S for each reaction would be greater than zero, less than zero, or too close to zero to decide.Given the following data 2 CIF (g) + O₂(g) → Cl₂ O(g) + F₂O(g) 2 CIF3 (9) +202 (g) → Cl₂ O(g) + 3F₂O(g) 2F2 (g) + O₂(g) → 2F₂O(g) calculate A H for the reaction AH= CIF (g) + F2 (g) → CIF3 (9) Submit Answer kJ Try Another Version ΔΗ = 167.4 kJ Δ Η = 341.4 Κ Δ Η = -43,4 kJ item attempt remainingGiven the following data: C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(l) DH = -1411.0 kJ 2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(l) DH = -3120.0 kJ 2 H2(g) + O2(g) → 2 H2O(l) DH = -571.6 kJ Calculate the enthalpy of the reaction: C2H4(g) + H2(g) → C2H6(g) DH = ___ kJ
- In a coffee-cup calorimeter, 110.0 mL of 1.2 M NaOH and 110.0 mL of 1.2 M HCl are mixed. Both solutions were originally at 22.5°C. After the reaction, the final temperature is 30.5°C. Assuming that all the solutions have a density of 1.0 g/cm³ and a specific heat capacity of 4.18 J/°C.g, calculate the enthalpy change for the neutralization of HCl by NaOH. Assume that no heat is lost to the surroundings or to the calorimeter. AH = 0.182 kJ/molCalculate AH for the reaction CH4(g) + 1/2O₂(g) → CO(g) + 2 H₂(g) given the following data: Equation CH4(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g) CH₂(g) + CO₂(g) → 2 CO(g) + 2 H₂(g) CH4(g) + H2O(g) → CO(g) + 3 Hz(g) ΔΗ = | Submit Show Hints Submit Answer kj Retry Entire Group ΔΗ (kJ) -802 247 206 9 more group attempts remainingUsing the equations H2 (g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C (s) + 2 F2 (g) → CF4 (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (g) → C2H4 (g) AH° = -97.6 kJ/mol %3D Determine the enthalpy (in kJ/mol) for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (g) + 4 HF (g).
- KOH(aq) + HBrO4 (aq) - 2CH₂CH₂CO₂H (1) + 70₂(g) KBrO₂ (aq) + H₂O(1) 6CO₂ (g) + 6H₂O(g) Mg(ClO3)₂ (s) → MgCl₂ (s) + 30₂(g) 2 Na₂S (aq) + FeCl₂ (aq) → 2NaCl(aq) + Fes (s) combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination O decomposition combination single replacement double replacement upply/ O decomposition O O precipitation single replacement O combustion double replacement acid-base precipitation combustion acid-base O precipitation combustion nacid-base precipitation combustion acid-base 8 目 000 18 ArThe sun supplies energy at a rate of about 1.0 kilowatt per square meter of surface area (1 watt = 1 J/s). The plants in an agricultural field produce the equivalent of 21 kg of sucrose (C12 H22 O11) per hour per hectare (1 ha = 10,000 m Assuming that sucrose is produced by the reaction m²). 12CO2 (9) + 11H2O(1) → C12H22O11(s) + 120O2(g) AH=5640 kJ calculate the percentage of sunlight used to produce the sucrose – that is, determine the efficiency of photosynthesis in this field. Percent efficiencyUsing the equations 2 CsHs (l) + 15 Oz (g) → 12 COz (g) + 6 H₂O (g)AH° = -6271 kJ/mol 2 H₂(g) + O₂(g) → 2 H₂O (g) AH° = -483.6 kJ/mol C (s) + O₂(g) → CO₂ (g) AH° = -393.5 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction. 6 C (s) + 3 H₂(g) → C6H6 (1).
- [References] Calculate AH for the reaction: 2NH3 (g) + O2(g) → N2H4 (1) + H2O(1) given the following data: 2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJ N2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJ N2H4 (1) + O2 (9) → N2(g)+2H20(1) ΔΗ--623 k.J На (9) + О2(9) — Н,0(1) AH = -286 kJ ΔΗ- kJ Submit Answer Try Another Version 3 item attempts remainingUsing the equations N2 (g) + O2 (g) → 2 NO (g) AH° = 180.6 kJ/mol N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol 2 H2 (g) + O2 (g) → 2 H2O (g) AH° = -483.7 kJ/mol %3D Determine the enthalpy (in kJ/mol) for the reaction 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (g).Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/mol H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g)+ NH3 (g)→ HCN (g) +3 H2 (g). %3D %3D ->