Given an array A of n positive numbers. The task is to find the first Equilibium Point in the array. Equilibrium Point in an array is a position such that the sum of elements before it is equal to the sum of elements after it. Example 1: Input: n = 5 A[] {1,3,5,2,2} %3! Output: 3 Explanation: For second test case equilibrium point is at position 3 as elements before it (1+3) elements after it (2+2).

Given an array A of n positive numbers. The task is to find the first Equilibium Point in the array. Equilibrium Point in an array is a position such that the sum of elements before it is equal to the sum of elements after it. Example 1: Input: n = 5 A[] {1,3,5,2,2} %3! Output: 3 Explanation: For second test case equilibrium point is at position 3 as elements before it (1+3) elements after it (2+2).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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You are given an array J[1 : n] which includes the scores of n players in a game. You are additionally given an array P[1 : m] with the score of m new players. Design and analyze an algorithm that given both arrays J and P, can find the rank of each player P inside the array J, i.e., for each P[i], determines what would be the rank of P[i] in the array consisting of all elements of J plus P[i]. Your algorithm should run in O((n + m) ·log n) time.
Given an integer array Arr of size N the task is to find the count of elements whose value is greater than all of its prior elements. Note : 1st element of the array should be considered in the count of the result. For example, Arr={7,4,8,2,9} As 7 is the first element, it will consider in the result. 8 and 9 are also the elements that are greater than all of its previous elements. Since total of 3 elements is present in the array that meets the condition. Hence the output = 3.
You are given an array A[1 : n] which includes the scores of n players in a game. You are additionally given an array B[1 : m] with the score of m new players. Design and analyze an algorithm that given both arrays A and B, can find the rank of each player B inside the array A, i.e., for each B[i], determines what would be the rank of B[i] in the array consisting of all elements of A plus B[i]. Your algorithm should run in O((n + m) ·log n) time.
there is array [4,3,4,3,3], each player hac has 10 points. Player takes out a number from their array and he substracts that number from his points and then computer plays with same rules . Game finishes when there is one element in array. In the end, whoever has more points , he wins.How to code it with MIN-MAX algorithm for computer to play?You can code it in Java, JavaScript, Python, C++
Given two arrays a and b, where both arrays consisting of n positive integers. It is allowed to swap any element from array a with any element from b. Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k moves (swaps). Input • The first line of the test case contains two integers n and k (1Sns30;0sksn) - where n is the number of elements in a and b, while k is the maximum number of moves you can do. • The second line of the test case contains n integers a1,a2,... an • The third line of the test case contains n integers b1,b2,..,bn Output Print the answer – the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps. Examples: Ex 1: Ex 2: Ex 3: Input 55 53 40 55665 1234 5 2243 12543 10 9 10 10 9 2423 Output: 27 39 11 • In the first test case of the example, you don't need to swap anything. • In the second test case of the example, you can swap a1=1 with bi=10, a3=3 with b3=10…
Given two arrays a and b, where both arrays consisting of n positive integers. It is allowed to swap any element from array a with any element from b. Your task is to find the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k moves (swaps). Input • The first line of the test case contains two integers n and k (1sns30;0sksn) - where n is the number of elements in a and b, while k is the maximum number of moves you can do. • The second line of the test case contains n integers a1,a2,... an • The third line of the test case contains n integers b1,b2,..,bn Output Print the answer – the maximum possible sum you can obtain in the array a if you can do no more than (i.e. at most) k swaps. Examples: Ex 1: Ex 2: Ex 3: Input 55 53 40 55665 12345 2243 12543 10 9 10 10 9 2423 Output: 27 39 11 • In the first test case of the example, you don't need to swap anything. • In the second test case of the example, you can swap a1=1 with b1=10, a3=3 with b3=10…
A unimodal array is an array that has a sequence of monotonically increasing integers followed by a sequence of monotonically decreasing integers, assuming all elements in the array are unique. Example: А- (4, 5, 8, 9, 10, 11, 7, 3, 2, 1}: A is a unimodal array because there is an increasing sequence followed by a decreasing sequence and the maximum element is 11. B= {11, 9, 8, 7, 5, 4, 3, 2, 1}: B is not a unimodal array because there is no increasing sequence It is simply a decreasing sequence and the maximum element is 11. C= {1, 2, 3, 4, 5, 7, 8, 9, 11}: C is not a unimodal array because There is an increasing sequence, but there is no decreasing sequence and the maximum element is 11. Design an efficient algorithm with the lowest possible complexity to state whether a given array is unimodal or not, and explain why your algorithm is efficient. Analyze the complexity of your algorithm.
Function PrintArray(integer array(?) dataList) returns nothing integer i for i = 0; i < dataList.size; i = i + 1 dataList[i] = Get next input Put dataList to output Put "_" to output // Your solution goes here. Modify as needed i = 0 Complete the PrintArray function to iterate over each element in dataList. Each iteration should put the element to output. Then, put "_" to output. Ex: If dataList's elements are 2 4 7, then output is: 2_4_7_ Function Main() returns nothing integer array(3) userNums integer i for i = 0; i < userNums.size; i = i + 1 userNums[i] = Get next input PrintArray(userNums)
You are given an array A[1 : n] which includes the scores of n players in a game. They areranked in the following way: Rank of a player is an integer r if there are exactly r −1 distinct scores strictlysmaller than the score of this player (irrespective of the number of players). Question: Design and analyze an algorithm that given the array A, can find the rank of all players in the arrayin O(n log n) time.
Given an array arr[] and an integer K where K is smaller than size of array, the task is to find the Kth smallest element in the given array. It is given that all array elements are distinct. Note :- l and r denotes the starting and ending index of the array. Example 1: Input: N = 6 arr[] = 7 10 4 3 20 15 K = 3 Output : 7.
Given an array A of n positive numbers. The task is to find the first Equilibium Point in the array. Equilibrium Point in an array is a position such that the sum of elements before it is equal to the sum of elements after it. Example 1: Input: n = 5 A[] = {1,3,5,2,2} Output: 3 Explanation: For second test case equilibrium point is at position 3 as elements before it (1+3) elements after it (2+2).
Given an array, find the total number of inversions of it. If (i < j) and (A[i] > A[j]), then pair (i, j) is called an inversion of an array A. We need to count all such pairs in the array. For example, Input: A[] = [1, 9, 6, 4, 5] Output: The inversion count is 5 There are 5 inversions in the array: (9, 6), (9, 4), (9, 5), (6, 4), (6, 5)