For the reaction: H2 (9)+ Br2 (9) = 2 HBr(g) K, = 3.6 x 10* at 1497 K. What is the value of K; for each of the following reactions at 1497 K? (a) 2 HBr(g) = H2(9)+ Br2 (g) Kp = (b) 글 H2 (g) + Br2(9) - HBr(g) Kp %3D (c) HBr(g) = H2 (g) + ¿ Br2 (g) K, 10 item attempts remainin Try Another Version Submit Answer

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