Find the total real power dissipation in a balanced delta-connected system. Phase voltage is 100V RMS, load impedance is 175Q, and power factor is 0.77 lagging 132W 507W O 2.33kW O 1.25kW
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- The actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power Is O 4000 VA CO 8000 VA O 6000 VÀ O 2000 VAIN THE CIRCUIT OF THE FIGURE THE LOADS ARE THE FOLLOWING: LOAD A: 4 KVA WITH F.P = 0.8 IN DELAY LOAD B: 2.4 KVA WITH F.P = 0.6 IN DELAY LOAD C: 1 KW AND 500 VA INDUCTIVE DETERMINE: a) Current I b) The power factor of the combination.There are two loads connected in parallel and powered from a 7200-V source. The first load is 50-kVA at 0.9 power factor lagging, and the second load is 45-kW at 0.85 power factor lagging. Determine the kind of KVAR and capacitance required to correct the overall power factor to 0.96 lagging.
- The actual impedance of a load is 30 OHM. The per-unit impedance of the load is 0.5 pu when Base Voltage is 600 V and Base Power is O 6000 VA O 2000 VA O 4000 VA 8000 VA3- phase power don't we need to multiply with 3? also Vt=13.1 KV, so shouldn't it be 13.1e3? in the power calc?Three-Phase Power Calculations
- If a load is leading, which statement is NOT true? a. The load is capacitive. b. It’s reactive power is positive. c. Current ahead of the voltage. d. Its power factor is positive.If a Load absorbs 10 kVA at a leading power factor of 0.6. Then the complex power is: Select one: a. -6000 - j8000 VA b. 6000 + j8000 VÀ c. 6000 - j8000 VÀ d. None of theseIn the circuit in the figure; L1 load draws 15 kVA with lagging power factor 0.6. The L2 load draws 6 kVA with a leading power factor of 0.8. According to this; What is the value of the complex power for the L2 load?
- If a Load absorbs 10 kVA at a leading power factor of 0.6. Then the complex power is: Select one: a. 6000 - j8000 VA b. 6000 + j8000 VÀ C. -6000 - j8000 VA O d. None of theseUse the information below to answer questions 24 und 25. The voltage across and the current through a load are (10+ j5Y and (2-jiArespecively. 24. What is the reactive power in VArconsumed? D. 0 A. 15 C. 20 D. 25 25. What is the pawer factor of the load? A. 0.8 leading B. 0.8 Jagging. -D. 0.6 ligging C 0.6 leadingThe circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT