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Find the points at which the following polar curve has a horizontal or a vertical tangent line. r=2 sin 20

Find the points at which the following polar curve has a horizontal or a vertical tangent line. r=2 sin 20

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 60E
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Find the points at which the following polar curve has a horizontal or a vertical tangent line. r=2 sin 20 At what points does the polar curve have a horizontal tangent line? OA. (0.2). (0.). (2,0,), and (±2,7 +0₁), where tan 0₁ = √/2 4√/2 4√2 + 3-0₁, where tan 0₁ = √2 OB. (0,0), (0,r), 3x 4√2 O C. 1 (0.). (0.²). (+41² 0₁). and (+4+²,2-0,), where tand, = -√2 4√2) (* 3 3-0₂ √√2 4√3 OD. (0,0), (0,r), , and and t 4√3 -0₁ , where tan 0₁ = √3 At what points does the polar curve have a vertical tangent line? ○ D. (0,0), (0,2), ( + 4√2,0₂), and (± 1 O A. (0,0), (0,), (±2,0₂), and (±2,x+0₂), where tan 8₂ = √√2 4√2 4√2 1 OB. t --0₂ 3 (0.5) - (0.-27). (+44² 0₂2). and (+44² 4-83). Where tan 02 and (2 - 4√³ x-₂): O C. (0.7), (0.37). (+ 4√³,0₂), 3 , where tan 0₂ = 4√/2 3-02, where tan 0₂ = √2 1 √√3
Transcribed Image Text:Find the points at which the following polar curve has a horizontal or a vertical tangent line. r=2 sin 20 At what points does the polar curve have a horizontal tangent line? OA. (0.2). (0.). (2,0,), and (±2,7 +0₁), where tan 0₁ = √/2 4√/2 4√2 + 3-0₁, where tan 0₁ = √2 OB. (0,0), (0,r), 3x 4√2 O C. 1 (0.). (0.²). (+41² 0₁). and (+4+²,2-0,), where tand, = -√2 4√2) (* 3 3-0₂ √√2 4√3 OD. (0,0), (0,r), , and and t 4√3 -0₁ , where tan 0₁ = √3 At what points does the polar curve have a vertical tangent line? ○ D. (0,0), (0,2), ( + 4√2,0₂), and (± 1 O A. (0,0), (0,), (±2,0₂), and (±2,x+0₂), where tan 8₂ = √√2 4√2 4√2 1 OB. t --0₂ 3 (0.5) - (0.-27). (+44² 0₂2). and (+44² 4-83). Where tan 02 and (2 - 4√³ x-₂): O C. (0.7), (0.37). (+ 4√³,0₂), 3 , where tan 0₂ = 4√/2 3-02, where tan 0₂ = √2 1 √√3
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