Find the number of addresses in the range if the first address is 14.7.24.0 and th last address is 14.7.27.255 Select one: a. 1024 b. 2048 C. 512 d. 256
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A: The given address is 12.2.2.7/24 Here the subnet mask is /24 This means total # of network+subnet…
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- Find the number of addresses in a block of classless addresses if one of the addresses is 12.2.2.7/24. Select one: a. 64 b. 128 C. 256 d. 32Buffer overlow :computer security In a C program, we print the address of relevant variables and arrays and get the following: 0xbfffe7b8 i 0xbfffe7bc length 0xbfffe7c0 hash_ptr 0xbfffe7ce targetuid 0xbfffe7d5 userid 0xbfffe817 pw 0xbfffe858 t 0xbfffe899 hashhex 0xbfffe8da target 0xbfffe91b hash 0xbfffe95c buffer The program executes the following instruction: strcpy(pw, buffer); You want to exploit the buffer overflow vulnerability by putting in buffer a string aaaaaaaaaaaaa ... 0c0beacef8877bbf2416eb00f2b5dc96354e26dd1df5517320459b1236860f8c with the goal of putting the hash 0c0beacef8877bbf2416eb00f2b5dc96354e26dd1df5517320459b1236860f8c variable target. If you count offset as 0 for the first a, 1 for the second a, and so on, what should be the offset of 0, the first character of the hash? In other words, how many a's should you put before the first zero character? (You can give the answer in decimal or in hexadecimal, but please specify.)How is an array stored in main memory? How is a linked list stored in main memory? What are their comparative advantages and disadvantages? Give examples of data that would be best stored as an array and as a linked list.
- 3. I/O Management: Disk Arm Scheduling & RAIDa. It is known that a disk drive has 256 cylinders, with cylinder numbers starting from 0 and ending at 255. The position of the needle on the disk drive currently stops at 128. It is also known that the needle always “goes to the cylinder with the smaller number first”. The order of the positions visited sequentially is: 254, 64, 32, 100, 50, 70. From the 3 choices of algorithms below, which one is the best algorithm? Make each image and determine the seektime.i. SCANii. C-SCANiii. FIFOHow will a number that is mathematically equivalent to be stored in memory as an 'int' value? Draw a small memory map for the int value to be starting at address 1000 (decimal). Be clear in your working. No marks for direct answer.given ASCIIOFSET .FILL x0030 NegASCIIOFSET .FILL xFFD0 ASCIINewline .FILL x000d ; Newline ascii code ASCIISpace .FILL x0020 ; Space ascii code ASCIIComma .FILL x002C ; Comma ascii code Use LC-3 I/O device to print number, commas, and spaces in printCommaSpace subroutine, also check code to see if it follows instructions and modify accordingly
- Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q uint16_t x = (uint16_t *)p; q[0]; aa aabb bbaa aabbccdd ddccbbaaPlease DO NOT respond to this question by copy/pasting the code provided elsewhere on the site, none of those work. Thanks. Virtual Memory Lab This lab project addresses the implementation of page-replacement algorithms in a demand-paging system. Each process in a demand-paging system has a page table that contains a list of entries. For each logical page of the process, there is an entry in the table that indicates if the page is in memory. If the page is in memory, the memory frame number that page is resident in is indicated. Also, for each page, the time at which the page has arrived in memory, the time at which it has been last referenced, and the number of times the page has been referenced since the page arrived in memory are maintained. The page table data structure is a simple array of page-table entries (PTEs). Each PTE contains five fields as defined below: struct PTE { int is_valid; int frame_number; int arrival_timestamp; int…Program this in java the state and variable display must be:Unsorted Partition Reference Index: 0, Traversing Index: 7, Current Traversing Index Value: mango, Next Index Value: plum, Swapping Condition: FalseCurrent Array: ['apple', 'avocado', 'orange', 'banana', 'strawberry', 'pineapple', 'plum', 'mango'] The input:["apple", "avocado", "orange", "banana", "strawberry", "pineapple", "plum", "mango"]Note:The sorted partition is on the left side. Then, the order is increasing based on the number of vowels of a string.the output must be like this:['plum', 'apple', 'strawberry', 'mango', 'orange', 'banana', 'avocado', 'pineapple']
- Ex 05- FIND C ? WHERE c is , A and B is stored in memory address AAAAA ,BBBBB an store the result C in adress CCCCC? C=[A( NB)Student information is being held in a data area, where each student record has the following format: The first nine bytes are the student number, held in ASCII The next byte is the course mark The next word is the section identifierThere are well over three hundred such student records that have been loaded sequentially into memory starting at address $10000. The last record loaded is a dummy record with a section identifier of $FFFF, to show the end of the records.Write an assembler subroutine GetMax that will scan the entire list and find the highest mark. If there is a tie, the first student in the list with the highest mark should be found. The subroutine should return the starting address of this record in address register a3.Write a program that can create a ‘short address' from a longer one. The program should be able to receivean address that has a fixed format but is of arbitrary length, and convert that to a specified shorter format.All input addresses will have the following format: address-line-1, address-line-2, ..., address-line-n, postcodeNote that there is a space character after each comma.All postcodes will have the following format:adddaa.Where a is an alphabetic character and d is a digit.For example, the address 56 Clapham Gardens, Stoke Newington, London, N145PX has the given format.As does 3 Acacia Ave, E178PU.The short address that your program generates must have the following format:address-line-1 postcodeNote that there is no comma in this string but there is a space between address-line-1 and postcode.For the examples above, the short addresses would be:56 Clapham Gardens N145PX and 3 Acacia Ave E178PU.Your class must contain the following method:public String…