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- The woman is trying to move the crate of weight W by pulling on the rope at the angle to the horizontal. Find the smallest possible tension that would cause the crate to slide and the corresponding angle .The 40-kghomogeneous disk is placed on a frictionless inclined surface and held in equilibrium by the horizontal force P and a couple C (C is not shown on the figure). Find P and C.V₂ - V₁ = 2 V₂ - V₁ = 1 3 P A modern art sculpture consists of a collar, a spring, and a circular track. The collar has a mass of m = 6 kg and the radius of the track is r = 1 m. If the spring is attached to a point P which is a vertical distance d = 0.3 m away from the perimeter of the circular track (d is measured between point 1 and point P), determine the change in potential energy between state 1 and state 2, and between state 1 and state 3. N The unstretched length of the spring is 0.15 m and the spring constant is k = 85- m UBC Engineering
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.The 250-N block rests upon a level plane for which fk = 0.2. It is pulled by force P = 100N inclined at 20o with the horizontal. If the 100-N pull is then removed, find the distance the block will travel.The figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure. Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (F₁) and (b) the normal force from the shoulder joint (F acting on the humerus bone that holds the arm in this equilibrium position. S (a) Number (b) Number i Fa 0.075 m O 12⁰ 0.250 m Units Units W arm 0.510 m 5 kg WA
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseThe 300kn sphere is supported by a pull p and a 200kn weight passing over a frictionless pulley. If a=30°. Computer the value of p and tangent.Equilibrium of Concurrent Force System. The piston of a reciprocating engine exerts a force of 175 kN on the crosshead when the crank is 45° (angle B) past TDC. If the stroke of the piston is 800 mm and the length of the connecting rod is 1.80 m, find the guide force and the force in the connecting rod. Hint: 1=½ stroke; Angle o may be solved using Sine Law in AACO. K= Compressive Force in the connecting Rod E= Piston Effort 70 120 F, = Guide Force Fig. P-1 Fig. P-2 a Tools: EF cos0=0; F sin .=0. R = Ev)* + (E#): ; R 771 =- : tane = sin A sin B sin C
- The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontalThe homogeneous box has mass m. The magnitude of force Pis slowly increased until motion occurs. Motion could occur as slipping or tipping and you must decide which occurs first. Find the value of P which first causes motion. A 33° = 0.40 B 2.0 d1.0m 3.0m 0.5m mi m2 PA N, 5. The drawing above shows two objects on a board supported at two locations. The m; = 40 kg (centered over P), m;=20 kg and m3=10 kg. c. Determine the force exerted by N2. (Take torques around P.) d. m2 rolls to the right. Just before the board starts to tip everything is balanced on N2 with no force on N1. Determine how far to the right of N2 m2 could roll without the board tipping. You might find it easier to take torques around a point rather than P.