Find the equation of the tangent line to the curve y=xVx +5 at the point (2,6).

Q: Find the equation of the tangent line to the curve y = √-4 at the point (5,1). Oy=-1 Oy=-1 Oy=2x-2

A: Given y=x-4       point (5,1)To find equation of tangent line:

Q: Find the equation of the tangent line at the given point on curve. ex2+ y2 = xe5y - y2e5x/2; (2, 1)

A: Given, ex2+y2=xe5y-y2e5x2:(2,1) To find the equation of tangent line at the given point on the…

Q: Find the equation of the tangent line to the curve y = x* + 3e" at the point (0, 3). y =

A: Equation of tangent to a function fx at point a,b is defined as y-b = m x-a where m is the slope of…

Q: Find an equation of the tangent line to the curve at thegiven point.

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Q: Find an equation of the tangent line to the curve y=2x^2+3 that is parallel to the line 8x-y+3=0

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Q: Find the equation of the tangent line to the curve y = 5x² - 7 at a point x = 1.

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Q: Find the slope of the tangent line to the curve 2x + 2xy + 2y = 32 %3D at the point (-4, 2).

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Q: Find an equation of the tangent line to the curve y = 7tan(5x) at the point (0, 1)

A: According to Bartleby only first question can be solved at a time Please find the solution

Q: Find the equation of the line normal to the tangent at the point (1,2) x’y+xy² = 6. on the curve

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Q: Calculate the equation of the tangent line to the curve r2 +ry+3r+2y-1 = 1 at the point (0, 1).

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Q: Find the equation of the tangent line to the curve y²(y² – 4) = x² (x² – 5) at the point (0, –2). |

A: Equation of tangent line is given by:y-y1=dydxx=x1·(x-x1)      .............[1]So first find dydx at…

Q: Find the slope of the tangent line to the curve 4x + 4cy- 4y° 276 at the point (- 1,4).

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Q: Find the slope of the tangent line to the curve – 2a2 + xy + 4y³ = - 6 3 at the point (- 2, 1).

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Q: Find an equation of the tangent line to the curve at the given point. у %3D sec(x), (л/3, 2) 2nv3 y…

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Q: Find the equation of the tangent line to the curve y x at the point 1, 4

A: We can find the equation of tangent line to the curve as below

Q: define the equation of the tangent line to the curve x^2-3xy+y^2-4x+2y+1=0 at the point (1,-1)

A: Given- The curve is x2-3xy+y2-4x+2y+1=0. To Find- The equation of the tangent line to the above…

Q: Find the equation of the tangent line.

A: Consider the given equation of curve:

Q: Find the slope of the tangent line to the curve 3a2 – 3xy – 4y3 = 56 at the point (2, – 2).

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Q: Find the equation of the tangent line to r - 3ry + y =-1 at (2,1).

A: Since you have posted multiple questions, as per our policy we will answer first question. Please…

Q: Find the tangent line at (-1,3) to the curve y* - 2xy – 27 =0

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Q: Find the equation of the tangent line to x + y = 9 %3D at the point (2, v5)

A: Equation of tangent to any curve y = f(x) at a given point ( x1, y1 ) is given by           ( y - y1…

Q: Find the equation of line tangent of y=x4-2x2+1 at (2,9)

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Q: Find an equation of the tangent line to the curve x2+y+y2=13 at the point (-1,3)

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Q: Find an equation of the tangent line to the curve y = 9" at the point (1, 10).

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Q: Find the slope of the tangent line to the curve 3x + læy + 3y° = - 199 %3D at the point (1, – 4).

A: we know that the slope of the tangent to the given curve is =dy/dx.

Q: Find the equation (in terms of x and y) of the tangent line to the curve r=4sin2θ at θ=π/3. y=?

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Q: Find the equation of the tangent line to the curve y = (5 – 3x)² at z = –5.

A: To find the equation of the tangent line to the below curve at x = -5. y=5−3x2

Q: Find an equation of the tangent line to the curve y = √ (3 + x2)that is parallel to the line x- 2y…

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Q: Determine the equation of the tangent line to the curve x- 2xy = 2y² +1 at the point (1:0).

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Q: What is the equation of the tangent line to the curve x? + 2y² = 4 at point (1, 1)?

A: Find your answer below

Q: Find the equation of the tangent line to the curve y=x4 at the point (−1,1).

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Q: Find the slope of the tangent line to the curve 4x^2-3xy+1y^3=26 at the point (3,2). Slope =

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Q: Find an equation of the tangent line to the curve at the point (0, 1). y = (1 + 3x)10 y =

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Q: Find an equation of the tangent line to the curve y = x/x that is parallel to the line y = 6 + 3x. y…

A: The given question has been solved in detail

Q: Find the slope of the tangent line to the curve - 2x2 + 2xy – 4y³ = 0 at the point (1, – 1). -

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Q: Find the slope of the tangent line to the curve -3x2 +3xy- 4y = - 247 %3D at the point (1, 4).

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Q: Calculate the equation of the tangent line to the curve 2x 3 + xy + 3x + y = 2 at the point (0, 2).

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Q: 2x2 y = Зх — 1

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Q: Find the slope of the tangent line to the curve x + xy – y = 23 at the point ( – 3, – 2). -

A: The given function is x2+xy-y3=23 The point is x0,y0=-3,-2

Q: Find an equation of the tangent line to the curve x^(2/3)+y^(2/3)=13 at the point (−27,−8).

A: Given:

Q: Find the equation of the tangent line to the curve y=2x2-1 at x=2

A: .

Q: Find the tangent line to the curve y = 2x - x2 at (2,0)

A: The equation of the curve is given by y = 2x-x2 The point is x0, y0 = 2, 0 Formula Used: The formula…

Q: Find the slope of the tangent line to the curve −2x^2+xy+2y^3=−8 at the point (−3,2)

A: NOTE: Refresh your page if you can't see any equations. .

Q: Find an equation of the tangent line to the curve xe + ye* = 2 at the point (0, 2).

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Q: . Find an equation of the tangent line to the curve y = x* + 1 that is parallel to the line 32x – y…

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Q: Find the equation of the tangent line to the curve y=x-6cos(x) at the point (0,-6)

A: We have to find equation of tangent line to the curve y=x-6cos(x) at the point (0,-6)  Now first we…

Q: Find the equation to the tangent line to the curve y = Vx³ – 2 where x 3 3

A: Please refer the attached image for complete solution.

Q: Find the slope of the tangent line to the curve 2x² 4xy + 4y³ = 10 at the point ( − 1, 1).

A: SOLUTION-

Q: Find the equation of the tangent line to the curve y = + 6x at its point of intersection with the…

A: The tangent of any given function is the line that touches the curve of the function at only one…

Q: Find the equation of the tangent line to the curve y = x* + 6e* at the point (0, 6). y =

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