Find F.I it. X(t) = 28 (t +27_²8 (x-2)-rect (t+1) 8-1 +rect +1) auso 4 (Sin² (w) - 25/uc (2W)) Hello expert, I want to solve the question step by step and in a clear line, please
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- How did he get the value inside the circle, can you explain step by step? The above spectoum be written as cam Y(F) = 12000 S(F+3000) + 12000 S(f-3000)+20000 S(CF+200+ 20000 8(f-200) 24000 SCF-3000) +24000 S(f+300D) + 2. y0000 S(f-2000) + yoo00 S(f+2000) 2. マ YE) - 24000 S(F-3000) + SIf+300) %3D 2 y0000 S(F-2000) + S(F+2000) 2 Step 2 of 2:) we know that Ac cos(27Tfct) < Fourier TransFom Ac SCF-fc)+ S(F+F)| APply Inve8se TOamsForm to Y(F) we get y (t) = 24000cos (21TX 3000 E) + 40000 COS 2T x 2000t %3D =) yE) = 2400ocos (G000TTE) + 40000 Cos (400 TE)1. Determine the Canonical form (Standard SOP) for AB + BC 2. Determine the Canonical form (Standard POS) of (A + B)(B+C) 3. Sketch the circuit diagram for a circuit that checks for odd prime numbers for the first 9 numbers ranging from 0 to 8. Use K map method for the simplification of the expression. 4. Use K map method to simplify the following expressions D+ A.C + B.CHi, please help me solve this. Thank you
- complete the routh table for the function 100 s5+2s4+4s³+5s²+s+2 Determine whether the response is stable or unstable. ins A S $² N 50 1 2 Blank 1 Blank 3 Blank 5 Blank 7 4 5 Blank 2 Blank 4 Blank 6 1 2Use a Karnaugh Map to reduce the expression to a minimum SOP form: A + B C’ + C DUse a Karnaugh map to find the minimum SOP form for each expressions AB+AB'C+ABC X=A'B'C'+A'B'C+AB'C X=AC(B'+C) =AC+AB'C X=A'B'C'+AB'C'+A'BC'+ABC'
- OVBr12Eo71MGsVR Join a Meeting- Zo. movies.awesomese.. 6 Question* s+3 If F (s) = then (s+1)(s-2) f(t) = e-2* (1 + 3e*) This option This option f() = f(t) = -et + 2e 3t This option This optionMATLAB R2022b-academ HOME ++ Cu... O New Open Save P |341433111 D... A W... Ⓒ Name col delt HE E_a Hi HJ kB kB_ kB latt latt M M_ |N n_n 1 2 3 Editor - C:\Us +7 MP5_5 N = n_sp J = kB = T1 = T2 = 5 6 7 8 9 10 11 12 13 2242972982 14 15 16 17 18 19 20 21 FILE 22 23 24 8 25 26 27 28 29 PLOTS CL fx >> n_mc n_pr latt latt % In M = E = M_ar E_ar % Mo tic; for Command Wind >> SW8 Tr Magnetiza Magnetiza Total tim Total tim ir 11,1,1,3,1,1,,,2,1,1,1,1, File 1 Page 4 of 5 Home Insert 0 words 1 Design V1 10V 10Hz R1 ww 1k92 Layout References capacmance across the nodes and 0? a) Circuit 1 b) Circuit 2 c) Circuit 3 d) Circuits 1 and 3 2 C1 10μF Mailings C2 10μF a) Circuit 1 b) Circuit 2 c) Circuit 3 d) Circuits 1 and 3 English (Philippines) 1 2 3 4 5 6・・・・・・ 7・・・・・ 8 C3 10μF Review Circuit 2 ru 1 V1 ru 10V 10Hz View Document1 - Word (Product Activation Failed) Tell me what you want to do... 1 R1 ww 1kQ T V1 10V 10Hz 0 R1 ww 1kQ 2 2 C3 HH 10μF C1 HH 10μF C1 HH 10μF 3 4 3 - និ C2 10μF C2 10μF Circuit…Draw the graph of -x(-(2t-1))
- Use a Karnaugh Map (K-Map) to minimize the following standard SOP expression F=AB'C+A'BC+A'B'C+A'B'C'+AB'C'Operation of Complex Number Given the following complex numbers, evaluate the following operations required in each item. Express your answer in POLAR FORM. Use the store-recall function in your calculator. a. T=106-108 +12022 B=(8-15)¹/3 M=(e/1.570796)-4 b. C. d. Acosh (3-j4) P=sin((52-306.8699°)*] e. f. X=(8)1430⁰ Based on the results from II.1 to 11.6, Evaluate the following expression: PASSED = In TEAMEE-235MATLAB R2022b-academ HOME ++ Cu... O New Open Save P |349933331 D... A W... Ⓒ Name col delt HE E_a Hi HJ kB kB_ kB latt latt M M_ |N n_n +7 1 2 3 Editor - C:\Us MP5_5 N = n_sp J = kB = T1 = T2 = n_mc n_pr 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 FILE 22 23 24 8 25 26 27 28 29 PLOTS 40 CL fx >> latt latt % IN N M = E = M_ar E_ar Command Wind >> SW8 Tr Magnetiza Magnetiza 3.2.1. % MO m tic; for Total tim Total tim File 1 11 Home Page 3 of 3 = Insert Design Layout References 0 words 2 For numbers 29 to 30, Given the circuit below. Complete the table of the missing information R1 www 12kQ V1 48V 3 Norton current (mA) Load voltage when R₁ = 2 k English (Philippines) 1 2 3 4 5 6・・・・・・ 7・・・・・ 8 Resonance frequency (Hz) Maximum current (A) Maximum voltage (V) Lower cut-off frequency (Hz) High cut-off frequency (Hz) Bandwidth R2 ww 8kQ Mailings R3 4kQ2 (31) (32) 10 1681 2305 RL 5kQ2 Review Calculated values (29) (30) For numbers 31 to 33, given the circuit below with L = 25.5 mH and C =…