f) As ATP is used, the above, at what ratio of equilibrium)? phosphocreatine stores are depleted. Using the ATP and ADP concentrations given [creatine]/[phosphocreatine] would you expect the reaction to stop (or reach G) do some research. How does the level of phosphocreatine remain high in muscle cells. Where/how is it remade from creatine? (one paragraph)

Biochemistry
9th Edition
ISBN:9781305961135
Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Chapter6: The Behavior Of Proteins: Enzymes
Section: Chapter Questions
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Energy Conversion Problem - 2022
1. a) Influence of concentration on the free energy change. In frog muscle, the concentrations of ATP, ADP,
and phosphate are 1.25x10-³ M, 0.50x10-³ M, and 2.50 x10-³ M respectively. Write the reaction and the reaction
quotient, Q. Calculate the free energy change, AG', for the hydrolysis of ATP in muscle cells. Assume that
AG"=-31.0 kJ mol-¹ for the hydrolysis of ATP, the temperature is 25°C, and the pH=7.
Q=(0.50x10-³ M)(1.25x10-³ M)/(2.50 x10-³ M) = 1.25 x 10-6 M/1.25 x 10-³ M = 1 x 10-³ M
A Gº'= -31.0 kJ/mol + (8.314 kJ /mol K_) (298 K) ( [0.5 × 10-³] [2.5 × 10-³] / [1.25 × 10-³])= −48.1 kJ/mol
b) For this system, what is the maximum amount of work that can be done per mole of ATP hydrolyzed?
W max, by the system =-W max, on the surroundings = -ArG' = 48.1 kJ/mol
c) In muscle, phosphocreatine serves as a carrier of chemical energy. It can transfer its phosphate group to ADP
to replenish the ATP used in muscle contraction. This is an example of energy coupling- using the energy of
a very favorable reaction to drive an unfavorable reaction. The enzyme creatine phosphokinase catalyzes
the reaction:
Net rxn
creatine phosphokinase
phosphocreatine + ADP
d) Show above how you calculate AGº' for the net reaction given that the hydrolysis for phosphocreatine is
AG0¹ -43.1 kJ mol-¹.
e) Calculate the equilibrium constant of this reaction.
phosphocreatine + H2O → creatine + Pi
Pi + ADP → ATP + H2O
= -43.1 kJ mol
= 31.0 kJ mol
creatine + ATP
bosphocreatine + ADP → creatine + ATP = -12.1 kJ mol
K-e 12.1 kj/mol / (8.314 x 10-³ kj/mol k) (298K)
K-e 4.89
K= 132.4
AG⁰¹ ???? kJ mol-1
f) As ATP is used, the phosphocreatine stores are depleted. Using the ATP and ADP concentrations given
above, at what ratio of [creatine]/[phosphocreatine] would you expect the reaction to stop (or reach
equilibrium)?
G) do some research. How does the level of phosphocreatine remain high in muscle cells. Where/how is it
remade from creatine? (one paragraph)
Transcribed Image Text:Energy Conversion Problem - 2022 1. a) Influence of concentration on the free energy change. In frog muscle, the concentrations of ATP, ADP, and phosphate are 1.25x10-³ M, 0.50x10-³ M, and 2.50 x10-³ M respectively. Write the reaction and the reaction quotient, Q. Calculate the free energy change, AG', for the hydrolysis of ATP in muscle cells. Assume that AG"=-31.0 kJ mol-¹ for the hydrolysis of ATP, the temperature is 25°C, and the pH=7. Q=(0.50x10-³ M)(1.25x10-³ M)/(2.50 x10-³ M) = 1.25 x 10-6 M/1.25 x 10-³ M = 1 x 10-³ M A Gº'= -31.0 kJ/mol + (8.314 kJ /mol K_) (298 K) ( [0.5 × 10-³] [2.5 × 10-³] / [1.25 × 10-³])= −48.1 kJ/mol b) For this system, what is the maximum amount of work that can be done per mole of ATP hydrolyzed? W max, by the system =-W max, on the surroundings = -ArG' = 48.1 kJ/mol c) In muscle, phosphocreatine serves as a carrier of chemical energy. It can transfer its phosphate group to ADP to replenish the ATP used in muscle contraction. This is an example of energy coupling- using the energy of a very favorable reaction to drive an unfavorable reaction. The enzyme creatine phosphokinase catalyzes the reaction: Net rxn creatine phosphokinase phosphocreatine + ADP d) Show above how you calculate AGº' for the net reaction given that the hydrolysis for phosphocreatine is AG0¹ -43.1 kJ mol-¹. e) Calculate the equilibrium constant of this reaction. phosphocreatine + H2O → creatine + Pi Pi + ADP → ATP + H2O = -43.1 kJ mol = 31.0 kJ mol creatine + ATP bosphocreatine + ADP → creatine + ATP = -12.1 kJ mol K-e 12.1 kj/mol / (8.314 x 10-³ kj/mol k) (298K) K-e 4.89 K= 132.4 AG⁰¹ ???? kJ mol-1 f) As ATP is used, the phosphocreatine stores are depleted. Using the ATP and ADP concentrations given above, at what ratio of [creatine]/[phosphocreatine] would you expect the reaction to stop (or reach equilibrium)? G) do some research. How does the level of phosphocreatine remain high in muscle cells. Where/how is it remade from creatine? (one paragraph)
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