EXAMPLE 6 Evaluate , y sin(xy) dA, where R = [1, 2] × [0, 7]. SOLUTION If we first integrate with respect to x, we get y sin(xy) dA = " J y sin(xy) dx dy = , (-cos 2y + cos y) dy = -} sin 2y + sin y = 0
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In the screenshot, how do you get from the first line to the second line? Meaning, how does the constant term y when
![EXAMPLE 6 Evaluate , y sin(xy) dA, where R = [1, 2] × [0, 7].
SOLUTION If we first integrate with respect to x, we get
y sin(xy) dA = " J y sin(xy) dx dy
= , (-cos 2y + cos y) dy
= -} sin 2y + sin y = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4126e26f-46ac-4d5a-aced-481192445f6b%2F5018cc5c-79ce-4c88-a814-1bd859ec1165%2F1cuskj9.png&w=3840&q=75)
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