Draw a generic engineering stress-strain diagram for a ductile metal and highlight the key strength points (yield, ultimate and fracture strength) on the curve. explain
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Draw a generic engineering stress-strain diagram for a ductile metal and highlight the key
strength points (yield, ultimate and fracture strength) on the curve. explain
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- The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.A specimen of steel 20 mm diameter with a gauge length of 200 mm is tested to destruction. It has an extension of 0.25 mm under a load of 80 kN and the load at elastic limit is 102 kN. The maximum load is 130 kN. The total extension at fracture is 56 mm and diameter at neck is 15 mm. Find . The stress at elastic limit. • Young's modulus. . Percentage elongation. Percentage reduction in area. Ultimate tensile stress. .
- A 19-mm reinforcing steel bar and a gauge length of 75 mm was subjected to ten- sion, with the results shown in Table P3.27. Using a computer spreadsheet pro- gram, plot the stress-strain relationship. From the graph, determine the Young's modulus of the steel and the deformation corresponding to a 150-kN load. TABLE P3.27 Load, kN Deformation, mm 54 0.084 163 0.168 284 0.336 330 1.428 366 3.360A steel specimen is tested in tension. The specimen is 25 mm wide by 5 mm thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 55 kN and fractured at 78 kN.a. Determine the tensile stresses at yield and at fracture.b. Estimate how much elongation would occur at 60% of the yield stress in a 50-mm gauge length.3. A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips. а. Determine the tensile stresses at yield and at fracture. b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length
- describe the terms: limit of proportionality, elastic stage, yield strength, ultimate tensile strength and fracture stressDiscuss the principles of stress and deformation analysis for several kinds of stressesA steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips. a. Determine the tensile stresses at yield and at fracture. b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length. Step-by-step solution: Step 1 of 4 Given that: Width of the specimen, b = 1 in Thickness of the specimen, t = 0.25 in Yield load on the specimen, Py = 12.5 kips Fracture load on the specimen, Pf = 17.5 kips Gauge length, L = 2 in Percentage of yield stress = 60%
- A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips.a. Determine the tensile stresses at yield and at fracture.b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length.A steel specimen is tested in tension. The specimen is 1 in. wide by 0.5 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 36 kips and fractured at 48 kips.a. Determine the tensile stress at yield and at fracture.b. If the original gauge length was 4 in., estimate the gauge length when the specimen is stressed to 1/2 the yield stress.3. Reproduce the table from NSCP 2015 showing the values of strength reduction phi under different conditions of strain in steel.
