Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with ribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 9% per year, which alternative hould be selected? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-100,000 $-30,000 $2,000 3 years LS $-300,000 $-5,000 $15,000 6 years
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- A manufacturer of automated optical inspection devices is deciding on a project to increase the productivity of the manufacturing processes. The estimated costs for the two feasible alternatives being compared are shown below. Use the internal rate of return (IRR) method to determine which alternative should be selected if the analysis period is 8 years and the company's MARR is 4% per year. Alternative M N Initial costs $30,000 $45,000 Net annual cash flow $4,500 $7,000 Life in years 8 8 (a) IRR of base alternative = (b) IRR of incremental cash flow = (c) Choose AlternativePARC Co. has asked you to recommend a new nutcracker machine. After months of hard research, you have collected the following data: Data Life, Years First Cost (FC) Benefit, Yearly (AB) Benefit Gradient (ABG) O&M cost Gradient (M&OG) O&M Cost uniform annual Salvage Value O 21 years O 12 years O 18 years KRAX 6 O 24 years $202,000 73,000 1,200 600 18,000 42,000 SPLIT-NUT 9 $285,000 88,000 PARC Co. assumes MARR = 15%. Using the Net Present Worth (NPW) analysis: The analysis period if you are going to use NPW is close to: 1,300 1,100 34,000 48,000Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 12% per year, which alternative has the lower present worth? The present worth for the DDM method is $ The present worth for the LS method is $
- Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 15% year, which alternative has the lower present worth? per Method DDM LS First Cost $-200,000 $-40,000 $-500,000 M&O Cost, per Year $-40,000 Salvage Value Life $2,000 $21,000 2 years 4 years The present worth for the DDM method is $ The present worth for the LS method is $ The (Click to select) v method is selected.A manufacturing company is trying to decide between the two machines shown below. Determine which machine should be selected on the basis of rate of return. Assume the MARR is 20% per year. Machine A Machine B Initial Cost, $ -18,000 -35,000 Annual operating cost, $/year -4,000 -3,600 Salvage value, $ 1,000 2,700 Life, years 3 6A company has a choice between two machines with identical production capacity but different costs. Use incremental rate of return analysis to determine which machine should be selected if the MARR is 8% per year. (Show you calculation process and make sure to indicate which machine should be selected). A B Initial cost $100 Annual benefit $20 Useful life (years) 10 $50 $12 10
- Old Southwest Canning Co. has determined that any one of four machines can be used in its chilicanning operation. The cost of the machines are estimated below, and all machines have a 5-year life. If the minimum attractive rate of return is 25% per year, determine which machine should be selected on the basis of a rate of return analysis. Machine First Cost, $ AOC, $ 1 −28,000 −20,000 2 −51,000 −12,000 3 −32,000 −19,000 4 −33,000 −18,000Consider VM * D' * s recent investment in the 3D MRI equipment. While this technology allows the Medical Imagining Center to stay at the forefront of technological developments in the field, it is currently underutilized. How would you propose to treat the new equipment from a costing system standpoint? Let's assume that the operating data of the new 3D MRI machine is the following: Initial Cost = $5, 000, 000 Useful life = 10 years Residual value = 0 Overhead costs (other than depreciation) per year =\$ 250000 Capacity = 2,500 hours / year Current utilization = 500 hours / yearA pipeline engineer working in Kuwait for the oil giant BP wants to perform a present worth analysis on alternative pipeline routings-the first predominately by land and the second primarily undersea. The undersea route is more expensive initially due to extra corrosion protection and installation costs, but cheaper security and maintenance reduces annual costs. Perform the annual worth analysis for the engineer at 12% per year as basis of choosing which route is to be selected. Land Undersea Installation cost P 315,000,000 P 450,000,000 Pumping, operating, security per year P 18,000,000 P 4,200,000 Replacement of valves and P 40,000,000 P 85,000,000 appurtenances in year 25 Life, years 50 50
- The engineers in a manufacturing company have proposed an investment of a newconcrete batching plant to improve the quality of their products. The estimates areshown in Table 2. The minimum attractive rate of return (MARR) of the companyper year is 15%. Table 2: Estimates of New Concrete Batching PlantEstimatesInitial investment $250,000Salvage value $50,000Annual operating cost $35,000Annual revenues $90,000Study period 10 years a. Calculate the equivalent annual worth (AW) of the given investment.b. What annual revenue should be attained to reach breakeven.Emerson Electric manufactures compressors for air conditioners. It needs replacement equipment to improve one of its manufacturing lines. Select between two options using the MARR of 14% per year and a future worth analysis for the expected use period. What are the future values of each option? Option First cost, S A B -64,000-76,000 -16,000-22,000 AOC, $ per year Expected salvage value 8,000 11,000 Expected use, years 3 6A warehouse manager is evaluating 2 different robotic systems to be installed in his warehouse. Using the present worth analysis, determine which is the economically better system if MARR is 12% per year compounded monthly. Justify your answer. System A System B - 40,000 -60,000 - 5,000 Initial cost, RM Maintenance cost, RM per month Semi-annual maintenance cost, RM per 6-month Salvage value after 5 years, RM - 13,000 8,000 10,000