Determine the patterns of inheritance of the following X-linked dominant cases by giving the results of the crosses between: a) affected male x normal female b) normal male x affected female c) affected male x affected female
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- Hemophilia A is transmitted by an X-linked recessive gene.With an affected father, what is the probability that a childwill have the disease? With an affected father and a carriermother, what is the probability?O. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S FHemophilia is determined by genes on the X chromosome in humans. Assume that a phenotypically normal woman whose father had hemophilia is married to a normal man. 1) What is the probability that their first son will have hemophilia? 2) What is the probability that their first daughter will have hemophilia?
- Ill.siven the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant, b) X-linked recessive, c) Autosomal dominant and d) Autosomal recessive in order to determine what is the mode of transmission of this trait. Disease allele = Xª, x², A or a depending on mode of transmission of the disease respectively. Unaffected X chromosome = X *Homozygous unaffected/No 1 *2 carrier=Normal II 1 *4 1 2 3 6. 7 8 a) X-linked dominant 11x12 b) X-linked recessive I 1 x1 2 c) Autosomal dominant 11x12 d) Autosomal recessive I1x12 IV. Based on your analysis what is the mode of transmission for this disease? O+10- A man with X-linked color blindness marries a woman with no history of color blindness in her family. The daughter of this couple marries a normal man, and their daughter also marries a normal man. What is the chance that this last couple will have a child with color blindness? Assume the chance to have a daughter or a son is equal. a) 3/8 b) 1/8 C) 1/16 d) 3/4 02040 e) 1/4 Boş bırakFemales with rr genotype are affected, males with rY are affected, females with Rr and RR are unaffected, males with RY are unaffected. a) sex-linked recessive b) autosomal dominant, homozygous lethal c) autosomal recessive d) autosomal dominant
- Consider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?Hemophilia is an X-linked recessive phenotype. Suppose a man who expresses the hemophilia phenotype has children with a woman who has the normal phenotype (and does not have a family history of hemophilia). If the couple have a son, what are the chances that he will have hemophilia? A) 50% B) 25% C) 0% D) 100%1. A) Apply the concept of sex linkage to explain why color blindness is more prevalent in men than in women. B) Mary is concerned that she may be a carrier for hemophilia, a sex-linked condition located on the X chromosome. Mary is married to John, who doesn't have hemophilia. Assuming Mary is a carrier, what are the genotype ratios expected for Mary and John's kids (specify for boys and for girls)? C) Mary and John have 2 boys, none of them has hemophilia. Can we use this fact as proof that Mary does not carry the allele for hemophilia? Explain your argument.
- Inheritance of sickle - cell anemia demonstrates_____ a ) Multiple allele inheritance c ) a dominant genetic disorder d ) incomplete dominance e ) a sex - linked inheritance3) Queen Victoria of England, who ruled from 1837-1901, is believed to have been the carrier of hemophilia. Hemophilia is an X-linked disease in which the blood is unable to form clots. Please make a Punnet Square using the scenario below and answer the following questions. Queen Victoria married a man who did not have the hemophilia trait or disease. What is the likelihood that they would have a child with hemophilia? What is the likelihood that they would have a son with hemophilia? What is the likelihood that they would have a daughter with hemophilia?A child has a blood type of “B positive”. This child is known to be a heterozygote at the ABO blood type gene and also a heterozygote at the Rh blood type gene. Select all of the choices below that show possible parents of this child.a) Genotypes IA IA X IA IAb) Genotypes IA IA X IA i c) Genotypes IA i X IA id) Genotypes IA IA X IA IBe) Genotypes IA IA X IB if) Genotypes IA IA X i ig) Genotypes IA i X i ih) Genotypes IA i X IB ii) Genotypes IB IB X IB IBj) Genotypes IB IB X IB ik) Genotypes IB IB X IA il) Genotypes IB IB X i im) Genotypes IB i X IB in) Genotypes IB i X i io) Genotypes IB IB X IA IBp) Genotypes IA IA X IB IBq) Genotypes IA IB X IA IBr) Genotypes IA IB X IA is) Genotypes IA IB X IB it) Genotypes IA IB X i iu) Genotypes i i X i iv) Genotypes + + X + +w) Genotypes + + X + -x) Genotypes + + X - -y) Genotypes + - X + -z) Genotypes - - X + -a1) Genotypes - - X - -