determine compound based on this spectrum data: MS Data- m/z = 112(45.45%), 113 (3.961 %), and 114 (0.195%) IR Peaks- 0.9 ppm (t, 6H), 1.5 ppm (dt, 4H), 2 ppm (td, 4H), 5.4 ppm (tt, 2H) C NMR Peaks- 15, 24, 36, and 127 ppm
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- The mass spectrum and 13C NMR spectrum of a hydrocarbon are shown. Propose a structure for this hydrocarbon, and explain the spectral data.When measured on a spectrometer operating at 200 MHz, chloroform (CHCl3) shows a single sharp absorption at 7.3 δ. (a) How many parts per million downfield from TMS does chloroform absorb? (b) How many hertz downfield from TMS would chloroform absorb if the measurement were carried out on a spectrometer operating at 360 MHz? (c) What would be the position of the chloroform absorption in δ units when measured on a 360 MHz spectrometer?Determine the molecular structure of the compound in the IR spectrum data, 1H NMR ; 13C NMR and MS, explain it for each picture.
- A student performed a series of reactions and obtained the spectral data provided. The reaction sequence is shown below.. What are the structures for A, B, C, and D? Compound B NMR (relative integrated areas below peaks) CH;CH,O°N 1. BHTHF N-bromosuccnimide A CH;CH,OH B 2. H,O,/OH- D hv reflux Compound A NMR (relative integrated areas below peaks) PPM 5 Compound B IR INFRARED SPECTRUM PPM 5 1 6 0.8 Compound A IR INFRARED SPECTRUM 0.6 0.8 0.4 0.4 0.2- 3000 2000 Wavenumber (cm-1) 1000 The MS of compound B shows an M+ peak at 198 and an M+2 peak at 200 with a relative abundance of 1:0.97 2000 Wavenumber (cm-1) 3000 1000 Transmitance Relative TransmittanceA compound has the molecular formula: C4H8O2 and gives the following H-1 NMR spectrum. Give the functional groups responsible for the signals, which integrate as 2H, 3H and 3H (downfield to upfield). nmrsim presentation 1 1 C: Bruker TopSpin3.5p17\examdata elle 3.0000 SODEŹ quartet is CH₂, singlet is CH3 and triplet is OCH3. quartet is CH3, singlet is OCH₂ and triplet is OCH3 quartet is CH₂, singlet is OCH3 and triplet is CH3. quartet is OCH₂, singlet is CH3 and triplet is CH3. quartet is OCH₂, singlet is CH₂ and triplet is CH3. POSE (ppm) 10 [rel]The spectra (IR, ¹H NMR, ¹³C NMR and MS) of an unknown compound are shown in the following spetta. Based on these spectra, determine the structure of the unknown compound. Explain your answers clearly for each spectrum. Absorbance/% IR 2000 1500 1000 500 50- 100+ 4000 11 1H NMR 3000 Integration 9 10 2500 7.95 7.25 U 2 2 8 7 Wavenumbers/cm-1 6 5 ppm 4.30 2 3 2.35 3 2 1.35 3 T 1 O
- Determine the compound (name or structure) from the data. Explain features from each data. Molecular formula: C6H5Br Use molecular formula to determine IHD IR: Identify the presence/absence of five key functional groups NMR: Analyze this last. Consider multiplicity and peak area to confirm compound. The 5 H peak area covers both peaks (at 7.1 and 7.5 ppm Structure?Which compound is correct for the given NMR spectrum? |(3) (2) (2) 2 1 PPM CN 1) 2) 3) Structure 1 O Structure 2 Structure 3The spectra (IR, 'H NMR, ®C NMR and MS) of an unknown compound are shown in the following spetra. Based on these spectra, determine the structure of the unknown compound. Explain your answers clearly for each spectrum. Ahserbance / IR 2000 Wavenumbers /em 13C NMR 130-128 14 61 145 22 167 160 140 120 200 180 100 PPm 80 60 40 20
- -·|· 4.0 Match the peaks in this spectrum with hydrogens on the structure below. A) I: 0.91 ppm II: 3.29 ppm III: 1.52 ppm IV: 3.23 ppm H3C | 3.0 || H₂ CH3 CH CH3 III IV 2.0 ppm 1.0 B) I: 0.91 ppm II: 3.29 ppm III: 3.23 ppm IV: 1.52 ppm C) 1: 3.23 ppm II: 3.29 ppm +Draw the structure of the compound whose spectroscopy data follows: MS m/z (% relative abundance): 77 m/z (40%), 79 m/z (20%), 105 m/z (100%), 154 m/z (21%), 156 m/z (7%) 00 3800 3600 3400 1200 1000 800 600 1800 1600 1400 3200 3000 2800 2600 2400 2200 2000 Wavenumber (cm") 2 2 3 6. 8 (ppm)Calculate the IHD of C7H6XNO and identify the important peaks in the following MS spectral data and draw the structure of the important peaks in the following MS spectral data.