def emotify(string): a=string.split() l=len(a) for i in range(0,l): if(a[i]=="smile"): a[i]=":)" if(a[i]=="grin"): a[i]=":D" if(a[i]=="sad"): a[i]=":((" if(a[i]=="mad"): a[i]=">:(" print (*a) string1=input("Enter the string:\n") emotify(string1); please explain this code. this is python
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def emotify(string):
a=string.split()
l=len(a)
for i in range(0,l):
if(a[i]=="smile"):
a[i]=":)"
if(a[i]=="grin"):
a[i]=":D"
if(a[i]=="sad"):
a[i]=":(("
if(a[i]=="mad"):
a[i]=">:("
print (*a)
string1=input("Enter the string:\n")
emotify(string1);
please explain this code. this is python
Step by step
Solved in 2 steps
- Counting hashtags Write Python code to count the frequency of hashtags in a twitter feed. Your code assumes a twitter feed variable tweets exists, which is a list of strings containing tweets. Each element of this list is a single tweet, stored as a string. For example, tweets may look like: tweets = ["Happy #IlliniFriday!", "It is a pretty campus, isn't it, #illini?", "Diving into the last weekend of winter break like... #ILLINI #JoinTheFight", "Are you wearing your Orange and Blue today, #Illini Nation?"] Your code should produce a sorted list of tuples stored in hashtag_counts, where each tuple looks like (hashtag, count), hashtag is a string and count is an integer. The list should be sorted by count in descending order, and if there are hashtags with identical counts, these should be sorted alphabetically, in ascending order, by hashtag. From the above example, our unsorted hashtag_counts might look like: [('#illini', 2), ('#jointhefight', 1),…def q5(sentence): Assumes sentence is a string. Returns a list of all the words in sentence, where a word is a token separated by white space, (you can use sentence.split()), and then for each word, make it lowercase and remove any character that is not alpha-numeric (a-z or 8-9). For example, I q5("The Plague" (French: "La Peste"), 1947, by Albert CamUs.') should return ['the', 'plague', 'french', 'la', 'peste', '1947', 'by', 'albert', 'camus'] q5('Red@Dragon....ca is great!') should return ['reddragonca', 'is', 'great'] passGiven: String[] name={"John", "Mary", "Jim", "Sam"}; Which one is correct: name[1]="Mary" name[1]="John" name.get(1)="Mary" name.get(1)="John"
- public static String[] getTokens(String raw, String delimiter){ // Line #1 goes here... int numTokens = st.countTokens(); // Line #3 goes here... for(int i = 0; i < numTokens; i++){ // Line #5 goes here } // Line #7 goes here } Using the code above, which one of these should be the code for "Line #7": ret[i] = st.nextToken(); return ret; String[] ret = new String[numTokens]; StringTokenizer st = new StringTokenizer(raw, delimiter);Fix the code to make it work properly pls // Converts a string to lowercase, and // displays the string's length // as well as a count of letters public class DebugSeven4 { public static void main(String[] args) { String aString = "HELP!! I need to get 37 things DONE today!!"; int numLetters = 0. int stringLength = aString.Length(); System.out.println("In all lowercase, the sentence is: "); for(int i = 0; i < stringLength; i++) { char ch = Character.toTheLowerCase(aString.charAt(i)); System.out.print(ch); if(Character.isLetter(ch)) numLetters--; } System.out.println(); System.out.println ("The number of CHARACTERS in the string is " + stringLength); System.out.println(The number of LETTERS is " + numLetters); } }write the following as a function that takes in a string and returns a string. for (int i=0; i != user_string. size(); i++){ if (islower(user_string[i])){ user_string[i]=toupper(user_string[i]); } elseif(isupper(user_string[i])){ user_string[i]=tolower(user_string[i]); } } cout<<user_string; return0; }
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string// Converts a string to lowercase, and // displays the string's length// as well as a count of letterspublic class DebugSeven4{public static void main(String[] args){String aString = "HELP!! I need to get 37 things DONE today!!";int numLetters = 0.int stringLength = aString.Length();System.out.println("In all lowercase, the sentence is: ");for(int i = 0; i < stringLength; i++){char ch = Character.toTheLowerCase(aString.charAt(i));System.out.print(ch);if(Character.isLetter(ch))numLetters--;}System.out.println();System.out.println("The number of CHARACTERS in the string is " + stringLength);System.out.println(The number of LETTERS is " + numLetters);}}DescriptionA researcher is analyzing DNA. A DNA can be represented as a string composed of the characters A, G, C, or T.One day, researchers found a strange DNA, which is Smooth Repeated DNA. The DNA is represented by a string that has infinite length. The string has a repeating pattern, i.e. the DNA string 0 is repeated an infinite number of times. For example, if0 = "????", then = "???????????? . . . ".According to researchers, a DNA is said to be special if it contains substrings . Determine whetheris a substring of . Squad FormatA line containing the two strings 0 and . Output FormatA line that determines whether it is a substring of . Issue “YES” ifis a substring of . Output “NO” otherwise. Example Input and Output Input Example Example Output AGCT GC YES AGCT TA YES AGCT GT No AGCT TAGCTAGCT YES AGGACCTA CTAA YES Explanation ExampleIn the first to fourth test case examples, is worth "???????????? . . . ". The part in bold is one of the…