d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 SUV Va Soom Vb 1000 ^ 200 + IT ix 100 τον t 200- ①Short circuit 750 2000-1 40000 №2 (900 зл Ra = + 200 = 1900 ~ 3 RT = t 1900 3 R+ = It= 200 2522 VT RT By COR: = 400 1 + 100 -1 + 500 SO = 0·19841 252 inx= 100 × 0.19841 200+100 i3 (T-1x=11 ix = 0.06614 0.19841 -0.06614 = 0.13227 100 75 152 7 1₁ =a.13227 13 500 iz Consider 15V source; 1700/3 ~ iz IT 200-n 400-2 t 75V 100 00 eT = (i 1700 + 400 IT = VT -1 +200 -434.46 75 RT 434.48 I = I + I2 200 400 IT 200♫ - + 750 13 = M 100 1527100 x 0.17262 13 = 0.0685 =0·17262A 12 = 400 1700 x0.0685 +400 = 18227 +0.0283 = 0.0283 =0·161 X

d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 SUV Va Soom Vb 1000 ^ 200 + IT ix 100 τον t 200- ①Short circuit 750 2000-1 40000 №2 (900 зл Ra = + 200 = 1900 ~ 3 RT = t 1900 3 R+ = It= 200 2522 VT RT By COR: = 400 1 + 100 -1 + 500 SO = 0·19841 252 inx= 100 × 0.19841 200+100 i3 (T-1x=11 ix = 0.06614 0.19841 -0.06614 = 0.13227 100 75 152 7 1₁ =a.13227 13 500 iz Consider 15V source; 1700/3 ~ iz IT 200-n 400-2 t 75V 100 00 eT = (i 1700 + 400 IT = VT -1 +200 -434.46 75 RT 434.48 I = I + I2 200 400 IT 200♫ - + 750 13 = M 100 1527100 x 0.17262 13 = 0.0685 =0·17262A 12 = 400 1700 x0.0685 +400 = 18227 +0.0283 = 0.0283 =0·161 X

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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