Cytochrome c oxidase catalyses the transfer of electrons from ferrocytochrome c to molecular oxygen. The balanced equation is shown below. 4 Cytochrome c(Fe 2") + O2 + 4 H*4 Cytochrome c(Fe ")+2H20 The relevant half reactions are: Cytochrome c(Fe ) +eCytochrome c(Fe 2* ) E, = +0.254V 4 O2 + 2 H* +2 e - H20 E = +0.816V (F = Faraday's constant = 96.485 kJ /V. mol, R= 8.314 J/mol.K) (i) What is the standard free energy change for this reaction? (ii) What is the equilibrium constant (K) for this reaction? ......

Human Anatomy & Physiology (11th Edition)
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Cytochrome c oxidase catalyses the transfer of electrons from ferrocytochrome c to molecular
oxygen. The balanced equation is shown below.
4 Cytochrome c(Fe 2") + O2 + 4 H* → 4 Cytochrome c(Fe * ) +2H:0
The relevant half reactions are:
Cytochrome c(Fe * ) + e Cytochrome c(Fe )
E, = +0.254V
½ O2 + 2 H* + 2 e H20
E.' = +0.816V
(F = Faraday's constant = 96.485 kJ /V. mol, R= 8.314 J/mol.K)
(i)
What is the standard free energy change for this reaction?
(ii)
What is the equilibrium constant (Keg) for this reaction?
Transcribed Image Text:Cytochrome c oxidase catalyses the transfer of electrons from ferrocytochrome c to molecular oxygen. The balanced equation is shown below. 4 Cytochrome c(Fe 2") + O2 + 4 H* → 4 Cytochrome c(Fe * ) +2H:0 The relevant half reactions are: Cytochrome c(Fe * ) + e Cytochrome c(Fe ) E, = +0.254V ½ O2 + 2 H* + 2 e H20 E.' = +0.816V (F = Faraday's constant = 96.485 kJ /V. mol, R= 8.314 J/mol.K) (i) What is the standard free energy change for this reaction? (ii) What is the equilibrium constant (Keg) for this reaction?
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