Considering the following procedure declaration in a language with dynamic scoping, what is the output produced if the parameter passing mechanism is • Pass by value • Pass by value-result • Pass by reference • Pass by name
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Considering the following procedure declaration in a language with dynamic scoping, what
is the output produced if the parameter passing
• Pass by value
• Pass by value-result
• Pass by reference
• Pass by name
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- int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?Problem: Feed Nibble Monster Till Full Write a program that generates a number in [0, 500] at the beginning -- this corresponds to how hungry the monster is -- and keeps asking the user to feed the monster until that number falls to zero. Each time the user feeds the monster a nibble, hunger decreases by the decimal value of the character (i.e. if the user feeds 'A' hunger decreases by 65). But when the user feeds the monster some character that isn't a nibble, the hunger increases by the decimal value of the character (since puking depletes energy). Use while loop. Sample runs: Notice the loop exits after one iteration, because hunger was very low and one nibble made the monster full: Notice hunger increasing after non-nibble (pink highlight): Notice that the program just keeps going when the user feeds the monster only non-nibbles. Do you think the program will keep running forever if the user never gives the monster nibbles?def main(): x = 1 y = 2 swap(x, y) print(x, y) def swap(s1, s2): temp = s1 s1 = s2 s2= temp main() Modify the code so that it actually swaps the values of x and y, without using the temp variable in the swap function.
- 1、Counting Primitive Operations void STRAITMAXMIN(A,n,max,min) //Set the maximum value in A to max and the minimum value to min { int i,n max=min=A[1] for i=2 to n { if A[i]> max max=A[i]; if A[i]< min min=A[i]; } }#include using namespace std; int find(int arr[], int value, int left, int right) { int midpt = (left+right)/2; if (left > right) return -1; if ( arr[midpt] return midpt; else if (arr[midpt] < value) == value) return else return find(arr,value, left,midpt-1); } void main(void) { int arr[] ={4,5,6,9,11}; cout<Problem Description The hailstone sequence is defined as the integer sequence that results from manipulating a positive integer value n as follows: If n is even, divide it by 2 (using floor division) • If n is odd, multiply it by 3 and then add 1 Repeat this process until you reach 1. For example, starting with n = 5, we get the sequence 5, 16, 8, 4, 2, 1. If n is 6, we get the sequence 6, 3, 10, 5, 16, 8, 4, 2, 1. If n is 7, we get 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1. If n is 8, we get the sequence 8, 4, 2, 1. As far as anyone can tell, this process will eventually reach 1 for any starting value, although mathematicians have been unable to formally prove this property as of yet. a. Write a Python function named hail () that takes a single integer argument. hail() should print out the sequence of numbers generated by applying the process above to the function parameter. This function does not return any value.Common Time Zones Function Name: commonTimeZones() Parameters: code1( str ) , code2( str ) Returns: list of common time zones ( list ) Description: You and your friend live in different countries, but you figure there's a chance that both of you might be in the same time zone. Thus, you want to find out the list of possible time zones that you and your friend could both be in. Given two country codes, write a function that returns a list of the time zones the two countries have in common. Be sure not to include any duplicate time zones. If the two country codes do not have any common time zones, return the string 'No Common Time Zones' instead. Note: You can assume that the codes will always be valid. example test cases: >>> commonTimeZones('can', 'usa') ['UTC-08:00', 'UTC-07:00', 'UTC-06:00', 'UTC-05:00', 'UTC-04:00'] >>> commonTimeZones('rus', 'chn') ['UTC+08:00'] For this assignment, use the REST countries API…Common Time Zones Function Name: commonTimeZones() Parameters: code1( str ), code2( str) Returns: list of common time zones ( list ) Description: You and your friend live in different countries, but you figure there's a chance that both of you might be in the same time zone. Thus, you want to find out the list of possible time zones that you and your friend could both be in. Given two country codes, write a function that returns a list of the time zones the two countries have in common. Be sure not to include any duplicate time zones. If the two country codes do not have any common time zones, return the string 'No Common Time Zones' instead. Note: You can assume that the codes will always be valid. example test cases: >>> commonTimeZones('can', 'usa') [UTC-08:00', 'UTC-07:00', 'UTC-06:00', 'UTC-05:00', 'UTC-04:00] >>> commonTimeZones('rus', 'chn') [UTC+08:00] For this assignment, use the REST countries API (https://restcountries.com/#api-endpoints-v2). For all of your requests, make…5- int fun() int a, b, c, result; cout>a>>b>>c; cout<<"The result is "; reutrn result; } The error is Your answer(-465)10 + (325)10 = ?int FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }C language Q4. Write a program that asks the user to enter an integer n, then prints the first n multiple of n. The program should keep asking to enter a number until -1 is entered. (0.5 point) Q5: a. What does the following program print? char c='Z'; for(i=1;i<= 4; i++) { for(j= 1; j<= i; j++) { printf("%c", C--); } printf("\n"); } b. Re-write the above code using while loop. Output: Sample Output: Enter a number: 4 48 12 16 Enter a number: 6 6 12 18 24 30 36 Enter a number: 1 1 Enter a number: -1 End Using while loop: (2x0.5 =1 point)SEE MORE QUESTIONS