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Consider the reaction: 3Fe2O3 (s) + H₂(g) → 2Fe3O4 (s) + H₂O(g) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.58 moles of Fe2O3(s) react at standard conditions. AS Substance AH (kJ/mol) Fe₂O3(s) -824.2 H₂(g) 0.0 Fe3O4(s) -1118.4 H₂O(g) -241.8 surroundings J/K 4

Consider the reaction: 3Fe2O3 (s) + H₂(g) → 2Fe3O4 (s) + H₂O(g) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.58 moles of Fe2O3(s) react at standard conditions. AS Substance AH (kJ/mol) Fe₂O3(s) -824.2 H₂(g) 0.0 Fe3O4(s) -1118.4 H₂O(g) -241.8 surroundings J/K 4

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter15: Energy And Chemical Change
Section: Chapter Questions
Problem 95A
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Consider the reaction: 3Fe2O3 (s) + H₂(g) → 2Fe3O4 (s) + H₂O(g) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.58 moles of Fe2O3 (8) react at standard conditions. AS Substance AH (kJ/mol) Fe₂O3(s) -824.2 H₂(g) 0.0 Fe3O4(s) -1118.4 H₂O(g) -241.8 surroundings = J/K 4
Transcribed Image Text:Consider the reaction: 3Fe2O3 (s) + H₂(g) → 2Fe3O4 (s) + H₂O(g) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.58 moles of Fe2O3 (8) react at standard conditions. AS Substance AH (kJ/mol) Fe₂O3(s) -824.2 H₂(g) 0.0 Fe3O4(s) -1118.4 H₂O(g) -241.8 surroundings = J/K 4
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