Consider the following SAS data and formula. Volume of sample at $1%: 50.2 ml 51% = 55% 52% = 70% Volume of SAS = [(volume of sample at S1%) (S2% - S1%)] / 100 [(1-(S2% / 100)] Calculate the volume of SAS needed for this experiment given this information.
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![Consider the following SAS data and formula.
Volume of sample at $1%: 50.2 ml
51% = 55%
52% = 70%
Volume of SAS =
[(volume of sample at S1%) (S2% - S1%)] / 100
[(1-(S2% / 100)]
Calculate the volume of SAS needed for this experiment given this information.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7332444e-698a-42cb-8d40-0b9e6764b3b2%2F1148f3a1-b9d6-4c5f-b887-94a67e367ae8%2Fsj0fj0w_processed.jpeg&w=3840&q=75)
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- A solution is prepared by diluting 2.81 mL of the blue dye stock solution to 25.00 mL. The measured absorbance for the prepared solution is listed in the data table. Measurement Result Blue dye stock solution 0.293 M Absorbance at 630 nm 0.00265 Calibration curve y=0.0833x Part: 0/3 Part 1 of 3 What is the theoretical molar concentration? Round your answer to 3 significant digits. [Blue]theoretical-M x10 X S Part: 1/3 Part 2 of 3 What is the experimental molar concentration? Round your answer to 3 significant digits. [Blue ] experimental M 9 Subm Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cent1. Certified Reference Material (CRM), GSS-5, is certified to contain 40.67 ± 3.33 mg/kg of Ni in soil. An analysis of the CRM gives values of 40.39, 41.98, 43.64, 44.38, and 45.96 mg/kg. Determine the tcalc. value and determine if your results differ from the expected results at the 90 % confidence level?ASSAY Calibration solutions Calibration solutions of naproxen in the range 5 – 25 μg/mL were prepared. Sample preparation 20 tablets weighing 12.3819 g were crushed to a fine powder. A portion of the powder (145.4 mg) was shaken with approximately 150 mL of acetic acid (0.05 M) for 5 min and then made up to volume in a 250 mL volumetric flask (stock solution). Approximately 50 mL of the stock solution was filtered and a 25 mL aliquot was diluted to 100 mL in a volumetric flask. 10 mL of the resulting solution was further diluted to 100 mL with acetic acid (0.05 M). Analysis The standards and sample solutions were analyzed by HPLC under the following conditions: Column: octadecylsilyl (ODS), 4.6 mmx150 mm, mobile phase: acetonitrile : 0.05 M acetic acid (85:15), flow rate: 1 ml/min, UV detection at 243 nm. Results: A calibration curve of concentration versus peak area was constructed for the standard solutions and gave the straight-line equation: y = 3555.6x + 85, r = 0.9999 The area…
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- You have a stock solution of 150.0±0.3 mg SO²/mL that has been certified by the manufacturer. You decide to dilute the solution by a factor of 100 to get a final concentration of 1.500 mg/mL. To do this, you use a 1.000±0.006 mL transfer pipette to transfer your stock solution to a 100.000.08 mL volumetric flask that you then dilute to the mark. Please calculate the absolute and relative error for the final concentration.Tubes 1-4 are standards with known mass and known volume of 200µL. Tubes 5-7 are unknowns that have been diluted 1/100 and volume used 200μL. How do you work out the concentration of tubes in g/L using a standard curve to work out the initial mass of unknowns. Tube No. 1 2 3 4 5 6 7 Protein amount (ug) 0 50 100 200 Absorbanc e (750nm) 0 0.32 0.5005 0.824 0.612 0.805 0.69Using the following mass standard data, calculate the Rx value. mass of mass of area of area of isopentyl acetate (g) isopentyl alcohol (g) isopentyl acetate peak isopentyl alcohol peak 80.0 1.10 1.28 189 Please report your answer to 3 decimal places. (No units required)