Consider the following model of a mechanical system: The system has a mass m, a linear spring with stiffness k, and two identical dampers with damping constant b. The left wall generates an input motion xin (t) that causes the mass to undergo a displacement x(t) from its equilibrium position. The initial position and velocity are zero. • Find the ODE describing the motion of the system by drawing a free-body diagram and applying Newton's 2nd Law. Your answer should be in terms of the following variables: Xin Xin, X, X, X, b,k, m Show that the transfer function is G(s): = X(s) Xin(s) $2 111 When taking the Laplace transform L[xin(t)] you may assume the initial (input) condition Xin(0) = 0.

Elements Of Electromagnetics
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3 Problem
Consider the following model of a mechanical system:
The system has a mass m, a linear spring with stiffness k, and two identical dampers with
damping constant b. The left wall generates an input motion xin (t) that causes the mass to
undergo a displacement x(t) from its equilibrium position. The initial position and velocity are
zero.
• Find the ODE describing the motion of the system by drawing a free-body diagram and
applying Newton's 2nd Law. Your answer should be in terms of the following variables:
Xin Xin, X, X, x, b,k, m
Show that the transfer function is
G(s) =
-
X(s)
Xin(s)
=
2b
m
k
s+
m
k
s²+ + m
When taking the Laplace transform L[xin(t)] you may assume the initial (input) condition
Xin(0) = 0.
Transcribed Image Text:3 Problem Consider the following model of a mechanical system: The system has a mass m, a linear spring with stiffness k, and two identical dampers with damping constant b. The left wall generates an input motion xin (t) that causes the mass to undergo a displacement x(t) from its equilibrium position. The initial position and velocity are zero. • Find the ODE describing the motion of the system by drawing a free-body diagram and applying Newton's 2nd Law. Your answer should be in terms of the following variables: Xin Xin, X, X, x, b,k, m Show that the transfer function is G(s) = - X(s) Xin(s) = 2b m k s+ m k s²+ + m When taking the Laplace transform L[xin(t)] you may assume the initial (input) condition Xin(0) = 0.
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