Consider a process with 4GB logical memory, 4KB page size, and a page table whose entry is 4B each. The page table of this process will be placed in one of the cache memories to increase performance. The size of L1, L2, and L3 caches are 64KB, 256KB, and 8MB, respectively. Investigate which cache memory can we use to fully place the page table.

Q: the AMAT (in number of clock pulses)?

A: The AMAT (in number of clock pulses)

Q: Given a computer using a byte-addressable virtual memory system with a two-entry TLB, a 2-way set…

A:

Q: Suppose a byte-addressable memory with 4 frames of size 32 bytes each and a paged virtual memory…

A: I will explain it in details,

Q: Given a 32-bit virtual address space featuring a 10-10-12 split and a 4-byte PTE size, suppose a…

A: The Answer is

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Q: Suppose the page table for process B that is currently executed on the processor is as in Table 1.…

A: List the logical address ranges for each page.       Given the following new ordered page…

Q: Consider a system with 256Mbytes of main memory with page size of 4Kbytes. It has a logical address…

A: Answer: Given Main Memory 256Mbytes           Page Size =4Kbytes  and logical address=26 bits

Q: 1. Consider a 32bit address space with 2K bytes page size, assuming that each entry consists of 4…

A: Solution : Address Space consist of 32 bits, program size is 2^32 bytes i.e. 4GB.   Page Size = 2K…

Q: For the following two questions assume that a computer uses a byte-addressable virtual memory system…

A: Dear Student, Virtual memory consists of 8bytes and it's byte addressable so number of blocks is 8…

Q: Consider a memory system that generates 16-bits addresses and the frame size is 32-byte. At time To…

A: According to the information given:- we have to find the maximum number of entries, page table…

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Q: For an old computing system with 2K bytes physical memory, and the virtual address has 13 bits.…

A:

Q: For a processor with a 32-bit address bus and a 64-bit data bus, 32 bytes of "line size" and a total…

A: A)  For fully associative cache,  Index bits is 0 So block offset bits = log (block size) = log 32B…

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A: Given Data : Block size = 8 words 1 word = 4 bytes Cache bits = 32 bits Address sending time = 1…

Q: Suppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per…

A: The answer is explained in detailed below:

Q: Consider a virtual memory system providing 32 pages for each user program; the size of each page is…

A:

Q: Draw the mapping cache memory for this system and view the details of the connection between cache…

A: SUMMARY: - Hence, we discussed all the output.

Q: Consider a computer with the following characteristics: total of 256Mbyte of main memory; block size…

A: Main memory size:256 MB = 28 x 220 Bytes = 228 Bytes Cache Block Size:8 Bytes = 23 Bytes Cache…

Q: Consider a system with 256Mbytes of main memory with page ize of 4Kbytes. It has a logical address…

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Q: Solve.  1.Consider a system with 2 level cache. Access times of Level 1, Level 2 cache and main…

A: Note the question is multiple one. We are advised to do only first question. Kindly post other…

Q: (a) Explain the use of TLBs to improve paging efficiency.  (b) Consider a paging system with the…

A: A). To overcome this problem a high-speed cache is set up for page table entries called a…

Q: Suppose a byte-addressable memory with 4 frames of size 16 bytes each and a paged virtual memory…

A: In this, we are asked about the TLB hit and physical address corresponding to the given virtual…

Q: Suppose the page table for a process A currently executing on the processor looks like the…

A: This is a multipart question, we are only allowed to solve 3 parts at a time, I am solving c, d, e…

Q: Consider a computer with a single off-chip cache with a 10 ns hit time and a 95% hit rate. Main…

A: As per Bartleby guidelines “Since you have posted a question with multiple sub-parts, we will solve…

Q: Given a 32-bit virtual address space featuring a 10-10-12 split and a 4-byte PTE size, suppose a…

A: The memory is split as  10 - 10 - 12 This means page size is 4KB. Now process size is 9MB Therefore…

Q: Consider a virtual memory system with a 50-bit logical address and a 38-bit physical address.…

A: A virtual memory system with a 50-bit logical address and a 38-bit physical address.Suppose that the…

Q: Consider a machine where total addressable physical memory size is 32 Kbytes. If we would like to…

A: total addressable physical memory size=32 Kbytes. we like to run 2 processes P and R as 8KB using…

Q: a microprocessor of 32 bit addresses, the tag length will change if we design a two-way…

A: A 2 way set associative cache means total number of block inside each set is 2 A 4 way set…

Q: Il- Consider a virtual memory system with the following properties: • 42-bit virtual byte address •…

A:

Q: Consider a cache memory with blocks of 23 words (1 word = 4 bytes) , with a bus Main Memory - Cache…

A: SUMMARY: -Hence, we discussed all the points

Q: Consider a rtual memory system with the following properties! • 42-bit virtual byte address • 32 KB…

A: Given Data :  Virtual address bits = 42 Page size = 32KB Physical address bits = 36  Valid bit = 1…

Q: Consider a computer with the following characteristics: total of 1Mbyte of main memory; word size of…

A: Main memory size = 1 Mbyte = 2²⁰ bytes  Word size = 1 byte  To address 1 word(i.e, 1 byte) number of…

Q: Assume that we have a paged memory system with a cache to hold the most active page table ent Ons to…

A: Cache access time = 20 ns = 0.02 microsecond Memory access time = 1 microsecond

Q: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…

A: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…

Q: Consider a system consisting of thirty-two bits virtual address, page size is 16 KB and a 512 lines…

A: The virtual address is of 32 bits. Whenever CPU wants any data from the memory, it  generates 32bit…

Q: Consider a 32-bit microprocessor, with a 16-bit external data bus, driven by an 8-MHz input clock.…

A:

Q: Consider a system with 4GB of memory address space. Assuming a write-back policy and block size of…

A: Memory size = 32 bits.  A.  Total # of cache blocks = 2K So index bits = 11 bits Offset bits = 5…

Q: Consider a system with 256Mbytes of main memory with page size of 4Kbytes. It has a logical address…

A: Below is the answer to above questions.

Q: Consider a computer system with a 32-bit logical address and 4-KB page size. The system supports up…

A: A)  Number of entries in conventional single level page table = number of pages in virtual address =…

Q: Consider a computer system with a 64-bit logical address and 32-KB page size. The system supports up…

A: 2) Consider a computer system with a 64-bit logical address space and 2-KiB page size. The system…

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A: The address of a process is first divided into equal-sized pages. These pages are kept under a table…

Q: Given a computer using a byte-addressable virtual memory system with a two-entry TLB, a 2-way set…

A: Below is the answer with explanation and calculation:

Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…

A: (1) it is given that: logical memory space = 30 bit = 2^30 bytes   given page size is 4KB = 2^12…

Q: Consider a paging system with the page table stored in memory. Memory access takes 200 nanoseconds.…

A: Introduction :Given , Paging system.Memory access time is = 200 ns page hit rate = 75 %TLB time =  0…

Q: Consider a computer with the following characteristics: total of 4 Mbyte of main memory; word size…

A: (a) F0010 = 1111 0000 0000 0001 0000 Word offset = 0000 = 0 Line = 0000 0000 0001 = 001 Tag = 1111…

Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…

A: Actually, 1 byte = 8 bits.

Q: Consider an 8-bit memory architecture that uses a single level page table with 4-bit page numbers…

A: Given Data : 8-bit memory architecture 4-bit page number. Page numbers are numbered from bottom to…

Q: Suppose a byte-addressable memory with 4 frames of size 8 bytes each and a paged virtual memory…

A: