COMPUTED REACTION CONSTANT BASED ON HALF LIFE: Assuming a first order reaction, 0.693 + 1/² 0.693 17 hrs, = 0.693 k = 17 hrs. k = 0.0407647... k = 4.02 x 10 hr. HOW MANY HOURS WILL IT TAKE TO ELIMINATE 23% OF THE DRUG AFTER THE INITIAL DOSE (SHOW YOUR COMPUTATION AND HALF-LIFE GRAPH:
COMPUTED REACTION CONSTANT BASED ON HALF LIFE: Assuming a first order reaction, 0.693 + 1/² 0.693 17 hrs, = 0.693 k = 17 hrs. k = 0.0407647... k = 4.02 x 10 hr. HOW MANY HOURS WILL IT TAKE TO ELIMINATE 23% OF THE DRUG AFTER THE INITIAL DOSE (SHOW YOUR COMPUTATION AND HALF-LIFE GRAPH:
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter11: Rate Of Reaction
Section: Chapter Questions
Problem 81QAP: The hypothetical reaction QR+Xproductswas monitored at 27C as a function of time. The following...
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![COMPUTED REACTION CONSTANT BASED ON HALF LIFE:
Assuming a first order reaction,
0.693
t
1/2
0.693
17 hrs, =
0.693
k=
17 hrs.
k = 0.0407647...
DOSAGE:
150 mg
hr.
k = 4.02 x 10
HOW MANY HOURS WILL IT TAKE TO ELIMINATE 23% OF THE DRUG AFTER THE INITIAL DOSE
(SHOW YOUR COMPUTATION AND HALF-LIFE GRAPH:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93098956-a2e0-40fc-bf75-819197ea6050%2Fdbc32bfe-b613-4127-ba0a-b2f4bf2b454a%2Fr8efltt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:COMPUTED REACTION CONSTANT BASED ON HALF LIFE:
Assuming a first order reaction,
0.693
t
1/2
0.693
17 hrs, =
0.693
k=
17 hrs.
k = 0.0407647...
DOSAGE:
150 mg
hr.
k = 4.02 x 10
HOW MANY HOURS WILL IT TAKE TO ELIMINATE 23% OF THE DRUG AFTER THE INITIAL DOSE
(SHOW YOUR COMPUTATION AND HALF-LIFE GRAPH:
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