Please solve all choices Clearly indicate if each of the following is True or False:1) Secondary treatment is a process consists of adding chemicals to remove BOD.2) Sequencing batch reactor requires two tanks, one for aeration and another for settling.3) Rotating biological contactor (RBC) is an attached growth system.4) Attached growth wastewater treatment system uses medium such as gravels or rocks.5) Critical point is the point where maximum deficit in dissolved oxygen occurs in rivers or lakes.6) Ozone in stratosphere layer helps prevent UV light from reaching earth and causing skin problems.7) Pure air can't containCO2 in it.8) PM10 refers to the fine particulates in air.9) Cyclone can be used to remove both particulates and SO2gas in a contaminated air.10) One disadvantage of the scrubber device is the visible plumes from factories use it.

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Answered: Clearly indicate if each of the…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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You have designed a treatment system for contaminant Z. The treatment system consists of two parts: (1) a pipe with a volume of 15 m3 and (2) a CSTR has a volume of 60 m3. The pipe feeds into the CSTR. The inflow to the pipe is 10 m3/d and the influent Z concentration at the start of the pipe is 2,500 mg/L. The effluent from the pipe has a Z concentration of 1500 mg/L. Assume the reaction is first order. What is the reaction rate constant in units of (1/day)?
A wastewater treatment plant uses an activated sludge process to treat 0.2 m3/s of primary effluent. The concentration of the mixed liquor is 2,000 mg/L MLVSS (Mixed liquor volatile suspended solids), while the RAS (recycled activated sludge) concentration is 10,000 mg/L MLVSS. The substrate concentration in the primary effluent is 210 mg/L BOD5. The F/M ratio is 0.5 mg BOD5/(mg MLVSS-d) and the solids retention time is 8.5 d. What is the volume of the activated sludge tank? 2.What is the WAS (waste activated sludge) flowrate? 3.What is the flowrate of the secondary treated effluent? 4.What is the RAS (recycled activated sludge) flowrate? 5.What is the hydraulic residence time for the activated sludge tank?
Q/ A wastewater treatment use an activated sludge process for secondary treatment of 10000 m/day for municipal wastewater. After primary clarification, The BOD is 150 mg/L, and it is desired to have not more than 7 mg/L of soluble BOD in the effluent. The mixed liquor has a concentration of 3000 mg/L and underflow solids concentration is 12,000 mg /L from the secondary clarifier. The kinetic constants from a bench scale treatability study are Y=0.5 and K=0.05 day". Assume the cell residence time is 10 days. Determine: a. The volume of the activated sludge tank & the hydraulic residence time. b. The sludge production rate & the sludge wasting flow rate. c. The sludge recycle ratio and recycle flow rate. d. The organic loading rate.
Example (Activated Sludge Process) - Completely Mixed with Recycle A completely mixed activated sludge process, treating a municipal wastewater, has a primary clarifier effluent BOD, of 135 mg/L. The design MLSS is 3590 mg/L, and the MLVSS is 80% of the MLSS. The plant permit is for an effluent BOD, of 20 mg/L and 20 mg/L suspended solids. The effluent suspended solids have a BOD, of 0.65 mg BOD, / mg suspended solids. The underflow solid concentration (MLVSS) is 10,000 mg/L. If umax = 3.0 day, Ks 60 mg/L, Y= 0.50 mg MLVSS / mg BOD, removed, ka= 0.1 day, and the influent flow is 0.25 m/sec, determine the following: 1. The required reactor detention time, 0. 2. The reactor basin volume, V, in m³. 3. The net waste activated sludge produced each day (kg/day). 4. The mass of solids (both volatile and inert) to be wasted each day (kg/day). The return sludge flow rate the recycle ratio. 6. The F/M ratio. 7 June 2021 Dr. Dawood Eisa Sachit Biological Wastewater Treatment 47
A coagulation treatment plant with flow of 0.5 metre cube per second is dosing alum at 23 milligram per litre. No other chemical is being added. The raw water suspended solid concentration is 37 milligram per litre. The effluent suspended solid concentration is measured as 12 milligram per litre. The sludge content is one percent and the specific gravity of sludge solid is 3.01 What volume of sludge must be disposed of each day? Based on your result, remark with reference to water treatment process.
MPN of effluent is 10/100 ml and it reduces to 102/100 ml after chlorination. Find percentage removal (%R) and log removal (logR) of MPN.
The sludge age 1. Is a measure of the time taken for sewage to stay in the bioreactor 2. Is one of the major parameters that controls the quality of the effluent 3. Determines the amount of solids to be wasted from the system 4. Is unaffected by the amount of solids in the effluent 2 and 3 1 only 1,2 and 3 1.2 and 4
The results of a jar test on a surface water supply sample revealed that the optimum dose of alum (Al2(SO4)3.14H2O) as coagulant is 17 mg/L. Furthermore, the water has total alkalinity = 50 mg/L as CaCO3; pH = 7.8; and residual turbidity at optimum alum dose = 4 NTU. The water treatment plant has a mean flow of 10m3/hour. Determine: The kg of alum per year needed in the operation of the plant. The residual alkalinity in the sample, following the addition of alum at optimum dose. Solve parts (a) and (b) if instead of alum, ferric chloride (FeCl3) were used as coagulant. Assume the numerical jar test results are the same as those with alum.
A 14 mgd wastewater treatment plant has a primary clarifier that treats an influent with 800 mg/L of solids and a removal efficiency of 55%. Sludge at the bottom of the tank is pumped at a rate of 0.1 mgd. 1. What is the effluent solids concentration from the clarifier (in mg/L)? What is the solids concentration in the sludge at the bottom of the tank (in mg/L and %)? The primary sludge is further processed in a digester following treatment. What weight of solids (in lbs) need to be handled each week? а. b. с.
12.60 The aeration tank for a completely mixed aeration process is being sized for a design waste- water flow of 7500 m³/d. The influent BOD is 130 mg/l with a soluble BOD of 90 mg/l. The design effluent BOD is 20 mg/l with a soluble BOD of 7.0 mg/l. Recommended design para- meters are a sludge age of 10 d and volatile MLSS of 1400 mg/l. Selection of these values takes stants from a bench-scale treatability study are Y into account the anticipated variations in wastewater flows and strengths. The kinetic con- 0.60 mg VSS/mg soluble BOD and k₁ = 0.06 per day. Calculate the volume of the aeration tank, aeration period, food ganism ratio, and excess biomass th
Problem 4In water and wastewater treatment processes a filtration device may be used to remove water from the sludgeformed by a precipitation reaction. The initial concentration of sludge from a softening reaction is 20,000 mg/Land the volume of sludge is 100 m3. After filtration the sludge solids concentration is 350,000 mg/L. Assume thatthe sludge does not change density during filtration, and there is no accumulation of sludge in the filtrationdevice. Using the mass balance method, determine the volume of sludge after filtration.
Chemistry A sewage treatment plant discharges 4 ML/d of effluent with 20.17 mg/L BOD5 into a stream. The stream discharge is 12 ML/d, and its initial BOD5 is 6.10 mg/L. The initial DO of the wastewater is 2.10 mg/L and in the stream, it is 7.91 mg/L. Assume the stream velocity is 0.31 m/s and the dissolved oxygen saturation concentration is 8.76 mg/L. The kd = 0.15 d-1 and kr = 0.31 d-1 values have been adjusted for temperature. Calculate the minimum DO in the stream and determine the distance (km) downstream that this minimum occurs. Is this a safe level for fish?

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