12 Note: This is a 2 point question. The reaction below is first order with respect to NO and second order with respect to Cl, Determine the value of the rate constant and write the rate law. 14 15 2 NO + Cl2 (e) (2) → 2 NOCI (e) Initial [NO] Initial [Cl] Initial Rate (M/s) 18 Experiment 0.0255 -- 0.0125 M 2. 0.0125 M 0.0510 21 0.0250 M 0.0255 4.55 x 10-5 3. Rate = 0.00370 M2s- [NOe]? [Clze] to O Rate = 2.79 M25- [NO)] [Clze]! Rate = 0.0712 M's'[NO2] [Cl} O Rate = 5.70 M's' [NO2]' [Cll² Rate = 5.70 M²²s²1 [NO]² [Cly«]' %3D Rate = 2.79 M2s1 [NO]' [C»el° Rate = 0.00370 M2s [NO2(2)] [C2el* Rate = 0.0712 M's[NO2] [Cl2(g)]
12 Note: This is a 2 point question. The reaction below is first order with respect to NO and second order with respect to Cl, Determine the value of the rate constant and write the rate law. 14 15 2 NO + Cl2 (e) (2) → 2 NOCI (e) Initial [NO] Initial [Cl] Initial Rate (M/s) 18 Experiment 0.0255 -- 0.0125 M 2. 0.0125 M 0.0510 21 0.0250 M 0.0255 4.55 x 10-5 3. Rate = 0.00370 M2s- [NOe]? [Clze] to O Rate = 2.79 M25- [NO)] [Clze]! Rate = 0.0712 M's'[NO2] [Cl} O Rate = 5.70 M's' [NO2]' [Cll² Rate = 5.70 M²²s²1 [NO]² [Cly«]' %3D Rate = 2.79 M2s1 [NO]' [C»el° Rate = 0.00370 M2s [NO2(2)] [C2el* Rate = 0.0712 M's[NO2] [Cl2(g)]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![12
Note: This is a 2 point question.
The reaction below is first order with respect to NO and second order with respect to
Cl, Determine the value of the rate constant and write the rate law.
14
15
2 NO
+ Cl2 (e)
(2)
→ 2 NOCI (e)
Initial [NO]
Initial [Cl]
Initial Rate (M/s)
18
Experiment
0.0255
--
0.0125 M
2.
0.0125 M
0.0510
21
0.0250 M
0.0255
4.55 x 10-5
3.
Rate = 0.00370 M2s- [NOe]? [Clze]
to
O Rate = 2.79 M25- [NO)] [Clze]!
Rate = 0.0712 M's'[NO2] [Cl}
O Rate = 5.70 M's' [NO2]' [Cll²
Rate = 5.70 M²²s²1 [NO]² [Cly«]'
%3D
Rate = 2.79 M2s1 [NO]' [C»el°
Rate = 0.00370 M2s [NO2(2)] [C2el*
Rate = 0.0712 M's[NO2] [Cl2(g)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc5e50f4-ebd6-48cd-987a-e5e72cd26647%2F1611445c-020b-4244-aa45-56381a3e7100%2Fnx7x29.jpeg&w=3840&q=75)
Transcribed Image Text:12
Note: This is a 2 point question.
The reaction below is first order with respect to NO and second order with respect to
Cl, Determine the value of the rate constant and write the rate law.
14
15
2 NO
+ Cl2 (e)
(2)
→ 2 NOCI (e)
Initial [NO]
Initial [Cl]
Initial Rate (M/s)
18
Experiment
0.0255
--
0.0125 M
2.
0.0125 M
0.0510
21
0.0250 M
0.0255
4.55 x 10-5
3.
Rate = 0.00370 M2s- [NOe]? [Clze]
to
O Rate = 2.79 M25- [NO)] [Clze]!
Rate = 0.0712 M's'[NO2] [Cl}
O Rate = 5.70 M's' [NO2]' [Cll²
Rate = 5.70 M²²s²1 [NO]² [Cly«]'
%3D
Rate = 2.79 M2s1 [NO]' [C»el°
Rate = 0.00370 M2s [NO2(2)] [C2el*
Rate = 0.0712 M's[NO2] [Cl2(g)]
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