Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration)/o. O 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100= SA solution "4" (0.400 mL stock to 10.0 mL) = 0.165 8 The SA is hydrolyzed and quantitatively transferred to a 100. mL volumetric flask, so: 1.1947/07 SA solution "3" (0.300 mL stock to 10.0 mL) = 138.1 (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 SA solution "2" (0.200 mL stock to 10.0 mL) SA solution "1" (0.100 mL stock to 10.0 mL) -1.1947 mol SA x10 g/mol 2762 -3 33 mol/L mol/L As-0-888 mol/L A+ = -695 mol/L A= 0.422 A₂ = 0.35 mol/L mol/L A₁ = 0. r these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach calibration curve with this report.

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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.107E
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Calculations.
1. Standard solutions and Beer's law calibration curve
(1) Mass of SA
Molar mass of salicylic acid (SA), HOC6H4COOH
(2) Moles SA = mass/molar mass
0,165
138.1
0,500
= (0.500/10.0)x(stock solution concentration) /o. 6
0.100
(3) Concentration of SA stock solution = mol/0.100L = (2)/0.100 =
SA solution "4" (0.400 mL stock to 10.0 mL)
= 0.1658
SA solution "3" (0.300 mL stock to 10.0 mL)
=
The SA is hydrolyzed and quantitatively transferred to a 100 mL volumetric flask, so:
11997 / 0
SA solution "2" (0.200 mL stock to 10.0 mL)
(4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL)
33
x 2762
=
SA solution "1" (0.100 mL stock to 10.0 mL)
138.1
-1.1947 mol SA
x 10
11
g/mol
33
2762
-3
mol/L
mol/L As=0-888
mol/L A+ = +695
0.422
A2 = 0.351
A₁ = 0,1
mol/L
mol/L
mol/L
A₁ = 0.
ter these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach
s calibration curve with this report.
Transcribed Image Text:Calculations. 1. Standard solutions and Beer's law calibration curve (1) Mass of SA Molar mass of salicylic acid (SA), HOC6H4COOH (2) Moles SA = mass/molar mass 0,165 138.1 0,500 = (0.500/10.0)x(stock solution concentration) /o. 6 0.100 (3) Concentration of SA stock solution = mol/0.100L = (2)/0.100 = SA solution "4" (0.400 mL stock to 10.0 mL) = 0.1658 SA solution "3" (0.300 mL stock to 10.0 mL) = The SA is hydrolyzed and quantitatively transferred to a 100 mL volumetric flask, so: 11997 / 0 SA solution "2" (0.200 mL stock to 10.0 mL) (4) Concentration of SA solution "5" (0.500 mL stock to 10.0 mL) 33 x 2762 = SA solution "1" (0.100 mL stock to 10.0 mL) 138.1 -1.1947 mol SA x 10 11 g/mol 33 2762 -3 mol/L mol/L As=0-888 mol/L A+ = +695 0.422 A2 = 0.351 A₁ = 0,1 mol/L mol/L mol/L A₁ = 0. ter these concentrations and absorbance in an Excel sheet and create a calibration curve. Attach s calibration curve with this report.
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