Calculate the standard enthalpy change for the reaction 2C8H18() + 1702(9) → 16CO(9) + 18H20(). Given 2C3H18(1)+ 2502(g) →16CO;(g) + 18H;O(1) AH°=-11,020 kJ/mol 2Co(g) + O2(g) → 2CO2(g) AH° =-566.0 kJ/mol Multiple Choice 10,450 k.J/mol -10.450 kJ/mol -6,492 kJ/mol 6,492 kJ/mol 15,550 kJ/mol

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section4.10: Standard Formation Enthalpies
Problem 4.18CE
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Calculate the standard enthalpy change for the reaction
2C8H18() + 1702(g) → 16CO(g) + 18H2O().
Given
2C3H15(1)+ 2502(g) →16CO2(g) + 18H2O(I) AH°=-11,020 kJ/mol
2Cog) + O2(g) → 2CO2(g)
AH° =-566.0 kJ/mol
Multiple Choice
10,450 kJ/mol
-10.450 kJ/mol
-6,492 kJ/mol
6,492 kJ/mol
15,550 kJ/mol
Transcribed Image Text:Calculate the standard enthalpy change for the reaction 2C8H18() + 1702(g) → 16CO(g) + 18H2O(). Given 2C3H15(1)+ 2502(g) →16CO2(g) + 18H2O(I) AH°=-11,020 kJ/mol 2Cog) + O2(g) → 2CO2(g) AH° =-566.0 kJ/mol Multiple Choice 10,450 kJ/mol -10.450 kJ/mol -6,492 kJ/mol 6,492 kJ/mol 15,550 kJ/mol
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