Calculate AS° for C(g) + 2 H₂(g) → CH₂(g). Substance C (g) C (g) H₂ (g) CH4 (g) Substance 2 5 8 Problem Table S° (J/mol.K) 5.7 130.6 186.2 J/mol K . 1 4 7 +/- ap here or pull up for additional resources 3 6 9 0 X C x 100
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- Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on, substance D HI chemical symbol, chemical formula or Lewis structure H HH ||| HHH Ar H I Ag -0. H H :O: H |||| HICIC-CIH H boiling point (Choose one) (Choose one) (Choose one) (Choose one)C(s, graphite) + H,O(g) → CO(g) + H, (g) ASixn J/mol·K 2 H,0,(1) 2 H,0(0) + О,(g) J/mol·K rxnCalculate the equilibrium constant (KP) for the following reaction at 25°C:
- Determine the boiling point of CS2, in °C, from the following data: AH (kJ mol-1) S° (J mol-1 K-1) CS₂(g) 115.3 237.8 CS₂(1) O-11 43 321 811 87 87.9 151.0Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on. chemical symbol, substance chemical formula boiling point or Lewis structure H H H A H – C C - C -0 H (Choose one) ▼ | H H Ag (Choose one) В Ar |(Choose one) - H :0: H Н— С — С С — Н (Choose one) v H. ? :0 : I - O - T(b) Study the following themochemical data very carefully: Ciz(g) - 2ci(g) I2(g) IC(g) - 1(g) + CI(g) I2(s) → 12(g) AH° = 242.3 kJ AH° = 151.0 kJ 21(g) AH° = 211.3 kJ AH° = 62.8 kJ I2(s) reacts with Cl2(g) to produce ICI(g). Write the chemical equation to produce ONLY one mole of ICI(g) (i) Calculate AH° for the reaction of I2(s) with Cl2(g) to form 1 mole of ICI(g). Use all the data given above. (ii) What law did you use to calculate AH° above? (iii) What are the names of the following processes? I2(s) → 12(g) I2(g) 21(g) ICI(g) I(g) + Cl(g)
- Given the following data: AHr [CH:(g)] = -75 kJ mol· C(graphite) → C(g) AH = +712 kJ mol 1/2H2(g) – H(g) AH = +215.5 kJ mol 13. The bond enthalpy in kJ mol·' of the C-H bond in methane is A +375 B +412 C 375 D -4121). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?From the following data, AH 393.5 kJ/mol C(graphite) 02g) -» CO2(g) H2g)02(g)-> H20() =285.8 kJ/mol AH 3119.6 kJ/mol 2CHg)702(g)- 4C02(g) + 6H2OC) calculate the enthalpy change for the reaction below: 2 C(graphite)3H2(g) -- C2H6(g) kJ
- Constants: • c = 2.9979 x 108 m/s • h = 6.626 x 10-34 J s per one photon • R = 8.314 J/(K mol) = 0.08206 L atm/(K mol) NA = 6.022 x 1023 particles/mol RH = 1.097 x 107 m1 = 2.178 x 10-18 J Ether has a Vapor Pressure of 385 torr at 20.0 °C. You dissolve 1.57 moles of a non-volatile compound (non-electrolyte) into 5.00 moles of Ether. What is the Vapor Pressure of Ether (in torr) above this solution at 20.0 °C?8,The following combination of signs for heat and work (respectively, heat first, work, next in the answer) represents a system that is gaining heat from the surroundings and doing work on the surroundings? Group of answer choices A, -; + B, +; - C, -; - D, +; + 23,The following intermolecular forces exist between the molecules of NH3 and acetone (CH3)2C=O: Group of answer choices A, dispersion, dipole-dipole, ion-dipole B, dispersion only C, dispersion, dipole-dipole D, hydrogen and dipole-dipoleMaterial from chapter 12, 15 2 NO2 (g) → N2O4 (g) a. Is this endothermic or exothermic? 6. AH = -57.23 kJ/mol b. If 5 mols of NO2 react, what is the amount of energy absorbed? SmoNOa=(-57.23KM).(512)= 143.075 dipele -dipile С. What intermolecular forces are present in NO2 (g)? d. Write the equilibrium constant expression. How does the equilibrium shift i. as the temperature is increased? ii. as more N204 (g) is added? iii. as the volume is decreased? e.