buse the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 4.8 M NH3. In 4.8 M NH3 the concentration of OH is 0.0093 M. Solubility: = mol/L

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.98QE
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a Using the
Kp value for
Cu(OH)2(
1.6 x 10-10) and the overall formation constant for
Cu(NH3)4²+
1.0 x 1013), calculate the value for the equilibrium constant for the following reaction:
Cu(OH)2()+4NH, (aq) Cu(NHs)
2+
(aq) + 20H (aq)
K: = 1.6x10^-6
b Use the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 4.8 M NH3. In 4.8 M NH3 the
concentration of OH is 0.0093 M.
Solubility
mol/L
Transcribed Image Text:a Using the Kp value for Cu(OH)2( 1.6 x 10-10) and the overall formation constant for Cu(NH3)4²+ 1.0 x 1013), calculate the value for the equilibrium constant for the following reaction: Cu(OH)2()+4NH, (aq) Cu(NHs) 2+ (aq) + 20H (aq) K: = 1.6x10^-6 b Use the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 4.8 M NH3. In 4.8 M NH3 the concentration of OH is 0.0093 M. Solubility mol/L
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