Blood typing in human depends on three alleles .The IA and IB alleles are codominant and and the O{i} allele is recessive. An IA IB blood type mother has childern with a B blood type father ( Genotype (IBi). What are the chances that there childern will have AB blood type? a.50% b.100% c.25% d.75% e.0%
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Question:-
Blood typing in human depends on three alleles .The IA and IB alleles are codominant and and the O{i} allele is recessive.
An IA IB blood type mother has childern with a B blood type father ( Genotype (IBi).
What are the chances that there childern will have AB blood type?
a.50%
b.100%
c.25%
d.75%
e.0%
Step by step
Solved in 2 steps
- Phenotypic ratio Type A : Type O = 2:2 or 1:1 Let's Try This! I1. Solve for the genetic problems below. One point each for: a. genotype of the parents b. Punnett square C. genotypic ratio d. phenotypic ratio e. type of Mendelian or non-Mendelian principle. Many kinds of wild animals have the agouti coloring pattern, in which each hair has a yellow band around it. a. Black mice and other black animals do not have the yellow band; each of their hairs is all black. This absence of wild agouti pattern is called nonagouti. When mice of a true-breeding agouti line are crossed with nonagoutis, the F1 is all agouti and the F2 has a 3 :1 ratio of agoutis to nonagoutis. Diagram this cross, letting A represent the allele responsible for the agouti phenotype and a, nonagouti. Show the phenotypes and genotypes of the parents, their gametes, the F1, their gametes, and the F2. b. Another inherited color deviation in mice substitutes brown for the black color in the wild-type hair. Such brown-agouti mice are called cinnamons. When wildtype mice are crossed with cinnamons, all of the F1 are wild type and the F2 has a 3 :1 ratio of wild type to cinnamon. Diagram this cross as in part a, letting B stand for the wild-type black allele and b stand for the…. Assuming no involvement of the Bombay phenotype(in case you’ve already read ahead to Section 3.2):a. If a girl has blood type O, what could be the genotypes and corresponding phenotypes of her parents?b. If a girl has blood type B and her mother has bloodtype A, what genotype(s) and correspondingphenotype(s) could the other parent have?c. If a girl has blood type AB and her mother is alsoAB, what are the genotype(s) and correspondingphenotype(s) of any male who could not be thegirl’s father?
- Answer the following questions. Letter's ONLY 1. A homozygous dominant parent (FF) and a heterozygous parent (Ff) are crossed. What is the genotypic probability of the offspring? * a. 100% Ff b. 50% Ff c. 50% FF and 50% Ff d. 50% Ff and 50% ff e. 50% dominant and 50% recessive f. 100% dominant 2. After performing an experiment on monohybrid cross about the shape of the pea seeds, data were obtained from the result. There are 87 wrinkled pea seeds and 313 round seeds. Of course, round seed is dominant over wrinkled seed. What is the expected value or ratio for the wrinkled seed? * a. 21.75 b. 65.25 c. 100 d. 300 e. 400 f. None of the choices97. This family is (picture above) affected with blindness. Individual (IV.1) is clinically unaffected. What is the chance that he is homozygous for the normal allele? A-½ B-% C- almost 0 D-1/3 E- almost 100% ANS: IV TO O 560-556Dihybrid Cross Practice In a breed of dog called a Doberman, black fur is dominant to brown fur and floppy ears are dominant to straight ears. These letters represent the genotypes and phenotypes of the dogs: EE = floppy ears Ee = floppy ears bb = brown fur ee = pointed ears BB = black fur %3D Bb = black fur 1. A female dog with the genotype BBee is crossed with a male dog with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. Ве Ве Ве Ве bE How many out of 16 have: black fur and floppy ears? be black fur and pointed ears? brown fur and floppy ears? bE brown fur and pointed ears? be
- Practice: 1.) Heterozygous A crosses with Heterozygous A. Calculate the probability of each phenotype being passed down to the offspring. TOTALS: (percent and ratio) A: B: AB: O: 2.) Type O breeds with Type AB TOTALS: (percent and ratio) A: B: AB: O: 3.) Woman has type B (exact genotype unknown). Man has type O. What are the possible blood types of their kids? Is this type possible: A: yes/ no? B: yes/ no? AB: yes/ no? O: yes/ no? 3B.) If the woman has a baby with type AB blood, could the man above be the father? Explain you answer.. For several years, Hans Nachtsheim investigated an inherited anomaly of the white blood cells of rabbits. Thisanomaly, termed the Pelger anomaly, is the arrest ofthe segmentation of the nuclei of certain white cells. Thisanomaly does not appear to seriously burden the rabbits.a. When rabbits showing the Pelger anomaly were matedwith rabbits from a true-breeding normal stock,Nachtsheim counted 217 offspring showing the Pelgeranomaly and 237 normal progeny. What is the geneticbasis of the Pelger anomaly?b. When rabbits with the Pelger anomaly were matedwith each other, Nachtsheim found 223 normal progeny,439 with the Pelger anomaly, and 39 extremely abnormalprogeny. These very abnormal progeny not only haddefective white blood cells, but also showed severedeformities of the skeletal system; almost all of themdied soon after birth. In genetic terms, what do yousuppose these extremely defective rabbits represented?Why were there only 39 of them?c. What additional experimental evidence…Mrs. Xexy Lucero, GO, 25 years old asks Nurse Zasha about pre symptomatic genetic testing for Huntington's disease. Nurse Zasha should base her response on which of the following? (Select all that apply) a. One of the parents died of Huntington's disease b. if the woman is negative for the gene, her children should be tested to see whether or not they are carriers c. Presymptomatic testing cannot predict whether or not the gene will be expressed. d. If the woman is positive for the gene Huntington's, she will develop the disease later in life e. Both parents are carriers
- ABO blood type in humans exhibits codominance and has multiple alleles A, B and O- the A and B alleles are codominant, and O is recessive. What is the likelihood of a type A father and a type A mother having a type O child? OA. It is impossible. B. 25% if both parents are heterozygous OC. 50% if both parents are heterozygous OD. 25% if only the father is heterozygous OE. 25% if only the mother is heterozygousThe ABO blood system has been used to settle cases of disputed paternity. Suppose, as a geneticist, you must testify during a case in which the mother has type A blood, the child has type O blood, and the alleged father has type B blood. How would you respond to the following statements? a. Mans attorney: The mother has type A blood, so the childs type O blood must have come from the father. Because my client has type B blood, he could not be the father. b. Mothers attorney: Further tests prove this man is heterozygous, so he must be the father.An a cross between two true-breeding plants, Parent #1 with yellow, round peas and Parent #2 with green, wrinkled peas, 1. a. What is the genotype of each plant in the cross. What proportion of the F1 progeny will have the same phenotype as Parent #2. After you self the F1s, what proportion of the progeny will have the same phenotype as Parent #1. C. What proportion of the progeny will have the same genotype as Parent # 1. d. b.