4:33 4 Alger Edit Today 4:31 PM O LIVE Which of the following statements regarding Mendel's observations and Laws are still true and part of our knowledge of genetics today? (Check all that true.) M Two alleles segregate during meiosis, ending up in different gametes. Each pea plant has 2 alleles for every gene, but only contributes one in each gamete. The recombination of alleles in a zygote is completely random. The Law of Independeht Assortment was determined by following three traits in pea plants, TMendle was able to determine his Law of Segregation by following ane trait in pea plants. Every offspring inherits only 1 allele from each parent. The following figure depicts red blood cells from a mother, a father, and their child. The mother and father are the biological parents of the child. Assume that both parents can be either homozygous or heterozygous for their blood type. What are all of the possible phenotypes (blood types) that the child could have? (Check all blood types that could be possible) A Mother's Blood Father's Blood Child's Blood Туре А Туре В (????) Type AB (IA IB) Type O (IL) Type B (IB IB or IB li) Type A (IA IA or IA li)

4:33 4 Alger Edit Today 4:31 PM O LIVE Which of the following statements regarding Mendel's observations and Laws are still true and part of our knowledge of genetics today? (Check all that true.) M Two alleles segregate during meiosis, ending up in different gametes. Each pea plant has 2 alleles for every gene, but only contributes one in each gamete. The recombination of alleles in a zygote is completely random. The Law of Independeht Assortment was determined by following three traits in pea plants, TMendle was able to determine his Law of Segregation by following ane trait in pea plants. Every offspring inherits only 1 allele from each parent. The following figure depicts red blood cells from a mother, a father, and their child. The mother and father are the biological parents of the child. Assume that both parents can be either homozygous or heterozygous for their blood type. What are all of the possible phenotypes (blood types) that the child could have? (Check all blood types that could be possible) A Mother's Blood Father's Blood Child's Blood Туре А Туре В (????) Type AB (IA IB) Type O (IL) Type B (IB IB or IB li) Type A (IA IA or IA li)

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section: Chapter Questions

Problem 30QP: Variations on a Theme by Mendel Pea plants usually have white or red flowers. A strange pea-plant...

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The Online Mendelian Inheritancein Man (OMIM) databaseis a catalog of human genesand human disorders that are inheritedin a Mendelian manner. Genetic disordersthat arise from major chromosomalaberrations, such as monosomyor trisomy(the loss of a chromosome orthe presence of a superfluous chromosome,respectively), are not included.The OMIM database, updated daily, is aversion of the book Mendelian Inheritancein Man, conceived and edited by Dr. VictorMcKusick of Johns Hopkins University,until he passed in 2008.The OMIM entries provide links to awealth of information, including DNAand protein sequences, chromosomalmaps, disease descriptions, and relevantscientific publications. In this exercise,you will explore OMIM to answer questionsabout the recessive human diseasesickle-cell anemia and other Mendelianinherited disorders.Exercise I – Sickle-Cell AnemiaIn this chapter, you were introduced torecessive and dominant human traits.You will now discover more about sicklecellanemia as an…
On rare occasions, an organism may have three copies of achromosome and therefore has three copies of the genes on thatchromosome (instead of the usual number of two copies). Forsuch a rare organism, the alleles for each gene usually segregateso that a gamete will contain one or two copies of the gene. Let’ssuppose that a rare pea plant has three copies of the chromosomethat carries the height gene. Its genotype is TTt. The plant is alsoheterozygous for the seed color gene, Yy, which is found on adifferent chromosome. With regard to both genes, how manytypes of gametes can this plant make, and in what proportions?(Assume that it is equally likely that a gamete will contain oneor two copies of the height gene.)
Match the observations about meiosis and crosses below with the corresponding principle developed by Mendel. A heterozygous individual [ Choose ] produces 50% of each gamete type. Alleles controlling different traits [ Choose ] can be transmitted to gametes in non-parental combinations. Each pair of homologous [ Choose ] chromosomes aligns and separates independently in metaphase and anaphase of meiosis I >
This pedigree (Pedigree #2) illustrates the inheritance of a simple Mendelian trait. If individuals III- 5 and III-6 have children, what are the chances that the children would have this disorder? 0% 1/4 2/3 O 1/6 ㅇㅁ
The Drosophila chromosome 4 is extremely small;virtually no recombination occurs between genes onthis chromosome. You have available three differentlymarked chromosome 4s: one has a recessive allele ofthe gene eyeless (ey), causing very small eyes; one hasa recessive allele of the cubitus interruptus (ci) gene,which causes disruptions in the veins on the wings;and the third carries recessive alleles of both genes.Drosophila adults can survive with two or three, butnot with one or four, copies of chromosome 4.a. How could you use these three chromosomes tofind Drosophila mutants with defective meiosescausing an elevated rate of nondisjunction?b. Would your technique allow you to discriminatenondisjunction occurring during the first meioticdivision from nondisjunction occurring during thesecond meiotic division?
The Drosophila chromosome 4 is extremely small;virtually no recombination occurs between genes onthis chromosome. You have available three differentlymarked chromosome 4s: one has a recessive allele ofthe gene eyeless (ey), causing very small eyes; one hasa recessive allele of the cubitus interruptus (ci) gene,which causes disruptions in the veins on the wings;and the third carries recessive alleles of both genes.Drosophila adults can survive with two or three, butnot with one or four, copies of chromosome 4.a. How could you use these three chromosomes tofind Drosophila mutants with defective meiosescausing an elevated rate of nondisjunction?b. Would your technique allow you to discriminatenondisjunction occurring during the first meioticdivision from nondisjunction occurring during thesecond meiotic division?c. What progeny types would you expect if a flyrecognizably formed from a gamete produced bynondisjunction were testcrossed to a fly homozygous for a chromosome 4 carrying both ey…
. In corn, the allele A allows the deposition ofanthocyanin (blue) pigment in the kernels(seeds), while aa plants have yellow kernels.At a second gene, W- produces smoothkernels, while ww kernels are wrinkled. Aplant with blue smooth kernels was crossedto a plant with yellow wrinkled kernels. Theprogeny consisted of 1447 blue smooth, 169blue wrinkled, 186 yellow smooth, and 1510yellow wrinkled.a. Are the a and w loci linked? If so, how farapart are they?b. What was the genotype of the blue smoothparent? Include the chromosomearrangement of alleles.c. If a plant grown from a blue wrinkled progenyseed is crossed to a plant grown from ayellow smooth F1 seed, what kinds of kernelswould be expected, and in what proportions?
A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) What kind of chromosomal aberration is shown? (b) Using a drawing, demonstrate how these chromosomeswould pair during meiosis. Be sure to label the differentsegments of the chromosomes.(c) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement? The woman in above problem has had two miscarriages. Shehas come to you, an established genetic counselor, with thesequestions:(a) If not, what is the chance that she could have a normalchild? Provide an informed response to her concerns
In a dihybrid cross of two heterozygous individuals, you expect a 9:3:3:1 phenotypic ratio in the offspring, but observe a ratio of 9:7. What is the most likely explanation? O Codominance O It is a sex-limited trait O Simple Mendelian inheritance O Incomplete penetrance O Epistatic interaction of the two genes
A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) What kind of chromosomal aberration is shown? (b) Using a drawing, demonstrate how these chromosomeswould pair during meiosis. Be sure to label the differentsegments of the chromosomes.(c) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement? The woman in above problem has had two miscarriages. Shehas come to you, an established genetic counselor, with thesequestions:(a) Is there a genetic explanation of her frequent miscarriages?
The human genome consists of 23 pairs of chro-mosomes (22 pairs of autosomes and one pair of sex chro-mosomes). During meiosis, the maternal and paternal setsof homologs pair, and then are separated into gametes, sothat each contains 23 chromosomes. If you assume thatthe chromosomes in the paired homologs are randomlyassorted to daughter cells, how many potential combina-tions of paternal and maternal homologs can be gener-ated during meiosis? (For the purposes of this calculation,assume that no recombination occurs.)
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