Başka yönergeler almak için tiklayın For the given system, obtain correct results and fill the boxes with correspounding values by using slope-deflection equations. All inputs distributed load and L1, L2, La lengths) are related with last digit of your student number. (You can assume El=1) (If you find a negative value at any step, you can right either negative or absolute in the boxes.) (But during your calculations, you have to take exact values into account. Only as a final result you can right absolute values in the boxes.) (Use. "dot" for decimals and submit your answer with 2 or 3 digits) INPUTS: Last digit of your number (170000000A) : A If A=0 THEN gu4 kN/m ; L=3 m ; L2=2 m; Lg=4 m IfA=1 THEN q=5 kN/m ; L1=4 m ; L2=3 m; L3=5 m IfA=2 THEN q=6 kN/m ; L1=5 m ; L2=4 m ; L3=6 m IfA=3 THEN q=7 kN/m ; L=6 m ; L2=5 m; L3=4 m IfA=4 THEN g=8 KN/m; L=7 m ; L2=6 m; L3=5 m If A=5 THEN g=4 kN/m ; Ly=8 m ; L2=7 m; L3=6 m IfA=6 THEN q=5 kN/m ; L=7 m ; Lg=4 m; L3=4 m If A=7 THEN q=6 kN/m ; L;=6 m ; L2=5 m; Lg=5 m

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question

A is 7 

Use 7 for A, 

A
В
D
L2
L3
+
Başka yönergeler almak için tıklayın
For the given system, obtain correct results and fill the boxes with correspounding values by using slope-deflection equations. All inputs (q distributed load and L1, L2, L3 lengths) are related with last digit of your student number.
(You can assume El=1)
(If you find a negative value at any step, you can right either negative or absolute in the boxes.)
(But during your calculations, you have to take exact values into account. Only as a final result you can right absolute values in the boxes.)
(Use. "dot" for decimals and submit your answer with 2 or 3 digits)
INPUTS:
Last digit of your number (170000000A) : A
If A=0 THEN q=4 kN/m ; L1=3 m; L2=2 m ; L3=4 m
If A=1 THEN q=5 kN/m ; L1=4 m ; L2=3 m ; L3=5 m
If A=2 THEN q=6 kN/m ; L1=5 m ; L2=4 m ; L3=6 m
If A=3 THEN q=7 kN/m ; L1=6 m ; L2=5 m; L3=4 m
If A=4 THEN q=8 kN/m ; L1=7 m ; L2=6 m; L3=5 m
If A=5 THEN q=4 kN/m ; L;=8 m ; L2=7 m; L3=6 m
If A=6 THEN g=5 kN/m ; L1=7 m; L2=4 m; La=4 m
If A=7 THEN q=6 kN/m ; L1=6 m ; L2=5 m ; L3=5 m
If A=8 THEN q=7 kN/m ; L1=5 m; L2=6 m; L3=6 m
If A=9 THEN q=8 kN/m ; L1=4 m; L2=7 m; L3=7 m
ANSWERS
Transcribed Image Text:A В D L2 L3 + Başka yönergeler almak için tıklayın For the given system, obtain correct results and fill the boxes with correspounding values by using slope-deflection equations. All inputs (q distributed load and L1, L2, L3 lengths) are related with last digit of your student number. (You can assume El=1) (If you find a negative value at any step, you can right either negative or absolute in the boxes.) (But during your calculations, you have to take exact values into account. Only as a final result you can right absolute values in the boxes.) (Use. "dot" for decimals and submit your answer with 2 or 3 digits) INPUTS: Last digit of your number (170000000A) : A If A=0 THEN q=4 kN/m ; L1=3 m; L2=2 m ; L3=4 m If A=1 THEN q=5 kN/m ; L1=4 m ; L2=3 m ; L3=5 m If A=2 THEN q=6 kN/m ; L1=5 m ; L2=4 m ; L3=6 m If A=3 THEN q=7 kN/m ; L1=6 m ; L2=5 m; L3=4 m If A=4 THEN q=8 kN/m ; L1=7 m ; L2=6 m; L3=5 m If A=5 THEN q=4 kN/m ; L;=8 m ; L2=7 m; L3=6 m If A=6 THEN g=5 kN/m ; L1=7 m; L2=4 m; La=4 m If A=7 THEN q=6 kN/m ; L1=6 m ; L2=5 m ; L3=5 m If A=8 THEN q=7 kN/m ; L1=5 m; L2=6 m; L3=6 m If A=9 THEN q=8 kN/m ; L1=4 m; L2=7 m; L3=7 m ANSWERS
ANSWERS:
Fixed End Moments:
(FEM)AB =
kNm
(FEM)BA =
kNm
(FEM)Bс 3D
kNm
(FEM)CB =
kNm
(FEM)cD =
kNm
(FEM)Dc =
kNm
Rotations:
Og =
8c =
Bending Moments at Member Ends:
MAB =
kNm
MBA =
kNm
MBc =
kNm
MCB =
kNm
McD =
kNm
Mpc =
kNm
Shear Forces at Member Ends:
VAB =
kN
VBA =
kN
VBc =
kN
Vce =
kN
VcD =
kN
Voc =
kN
Transcribed Image Text:ANSWERS: Fixed End Moments: (FEM)AB = kNm (FEM)BA = kNm (FEM)Bс 3D kNm (FEM)CB = kNm (FEM)cD = kNm (FEM)Dc = kNm Rotations: Og = 8c = Bending Moments at Member Ends: MAB = kNm MBA = kNm MBc = kNm MCB = kNm McD = kNm Mpc = kNm Shear Forces at Member Ends: VAB = kN VBA = kN VBc = kN Vce = kN VcD = kN Voc = kN
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