based on your data, is acetic acid more soluble in water or ethyl acetate? How about water versus toluene?

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 11E: The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities...
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based on your data, is acetic acid more soluble in water or ethyl acetate? How about water versus toluene?
DATA SHEET: DISTRIBUTION COEFFICIENT
Name: 2horik Selena Camelo
Equiv. wt. of acetic acid
60 g/moL
10.10 mL
a.
Volume of base required for first titration
0.01010 L
or
b. Mass of acetic acid in the 10 mL aliquot 0.2 aot x0.0101XX 609
0.1212 8
0.2
Formula: massacid = (N X V)base X (Equiv. wt.)acid
Inoot
6.53 mL
с.
Volume of base required for second titration
O.00653 L
or
d. Mass of acid left over in water layer 0.2 xo.o06534x 609
I met
0.07836 8ACOH in H,O
Use the same formula as in (b)
IK
Mass of acid in ethyl acetate after a single 10 mL extraction
е.
.04284 g ACOH in ETOAC
Item (b) – item (d)
O. 1212g-0.07836 =0.04284
1 x 10 mL extraction
(starting g ACOH in 10 mL aliquot-g ACOH remaining in H,O = g
ACOH in EtOAC)
6,29 mL
f.
Volume of base required for third tritraion
0.00629 L
or
g. Mass of acid in water layer
0.20
X 0. 00629X x 60g
.07548 g ACOH in H,O
Use the same formula as in (b)
h. Mass of acid in ethyl acetate after two 5 mL extractions
04572 g ACOH in EtOAc
Item (b)- item (g)
O. 1212g-0.01548g =0.04572
2 x 5 mL extractions
i.
Distribution coefficient (K,) of acetic acid in ethyl acetate
0-04284g
0-078369
0.04572 g
0.018369
= 0.6057
=0.5467
Item (e) / item (d)
vs.
Item (h) / Item (g)
K, (single extraction) . 5467
K, (double extraction) 6051
5 | Page
Transcribed Image Text:DATA SHEET: DISTRIBUTION COEFFICIENT Name: 2horik Selena Camelo Equiv. wt. of acetic acid 60 g/moL 10.10 mL a. Volume of base required for first titration 0.01010 L or b. Mass of acetic acid in the 10 mL aliquot 0.2 aot x0.0101XX 609 0.1212 8 0.2 Formula: massacid = (N X V)base X (Equiv. wt.)acid Inoot 6.53 mL с. Volume of base required for second titration O.00653 L or d. Mass of acid left over in water layer 0.2 xo.o06534x 609 I met 0.07836 8ACOH in H,O Use the same formula as in (b) IK Mass of acid in ethyl acetate after a single 10 mL extraction е. .04284 g ACOH in ETOAC Item (b) – item (d) O. 1212g-0.07836 =0.04284 1 x 10 mL extraction (starting g ACOH in 10 mL aliquot-g ACOH remaining in H,O = g ACOH in EtOAC) 6,29 mL f. Volume of base required for third tritraion 0.00629 L or g. Mass of acid in water layer 0.20 X 0. 00629X x 60g .07548 g ACOH in H,O Use the same formula as in (b) h. Mass of acid in ethyl acetate after two 5 mL extractions 04572 g ACOH in EtOAc Item (b)- item (g) O. 1212g-0.01548g =0.04572 2 x 5 mL extractions i. Distribution coefficient (K,) of acetic acid in ethyl acetate 0-04284g 0-078369 0.04572 g 0.018369 = 0.6057 =0.5467 Item (e) / item (d) vs. Item (h) / Item (g) K, (single extraction) . 5467 K, (double extraction) 6051 5 | Page
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