Based on the given Boolean Expression below please simplify the expression and draw the logic circuit diagram based on the simplified expression. Q = X'Y'Z' + X'Y'Z +X'YZ' + XY'Z'
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- Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CSimplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.DDraw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = F
- Simplify the following Boolean expressions using Karnaugh Map and draw the logic circuits. f = wxyz + wxyz + wxyż + wxỹz + wxyz + wxyz + wxỹz + wãyzProblem: Derive the logic expressions for a circuit that compares two unsigned numbers: X = x2x1xo and Y = = y2y1yo and generates three outputs: XGY, XEY, and XLY. One of these outputs is set to 1 to indicate that X is greater than, equal to, or less than Y, respectively.4. For the logic circuit shown in Figure below write the required input condition (A,B,C) to make the output X =1. A B
- A three input logic functipn will provide a logic high output only when twp (and two only) of the inputs are logic highs. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. Y=A'B'C+A'BC'+AB'C' B. Y=AB'C+A'BC+ABC' C. Y=AB'C+ABC+A'B'C' D. Y=ABC'+AB'C+A'B'C'Consider the multiplexer based logic circuit shown in the figure MUX MUX 1 Select one: a. W S1' S2' O b. W + S2 + S1 c. WS1 + WS2 + S1 S2 O d. WeS1es2Q.No.10: Draw Combinational Logic Circuit for the following Boolean expression i.e. one combine circuit for each expression? *Then simplify and prove the problems i.e. Boolean expression using Boolean rules and laws as discussed in the class. E.g. prove it with the help of Boolean rules and law that B+BC=B, how? (i) B+BC=B (ii) B+BC=B+C (iii) (B+C)(B+D)=B+CD
- 2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CTask 3: Digital logic circuit analysis - Finding the Boolean expression of a given circuit Find the Boolean expression of the following circuit, draw the circuit on EWB and simulate it to fill-in its truth table shown below. W = Note: the logic converter tool from EWB to fill-in the following table. For that, you need to connect the A, B and C inputs of the logic converter to X, Y and Z lines, respectively. Further, you need to connect the "out' line of the logic converter to W. As shown in the following diagram EDHAIB Logic Converter 000000O00 ABCDEFGH Conversions 1OT AB + 10E + NAND AB C'+A B'C+AB C+AB C+ABC+ABC X(B)- Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+ (C+ B).D 2) Y= A.B.C+B. D. (A OB)+C 3) Y= A.B (C+ D) +D+ A OB