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- Problem 4 From the figure, w1 =13kN/m, w2=10kN/m, F1 =7kN 1. Find the resultant of the forces 2. Find the location of the resultant from point B. 7m 4m 2mSituation 1- For the forces shown in the Figure AP-4.1: 1. Determine the X-component of P= 300 N A the resultant force in Newtons. Answer: 185.12 N 2. Determine the Y-component of the resultant force in Newtons. Answer: 117.37 N 3. Determine the moment about point O due to forces, in N-m. Answer: 107.87 N-m 0.2 m BI R= 100 N Q = 150 N 0.2 m Figure AP-4.1F1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m bo
- for the following system, assume tension in cable BC=10 kN, and in BD= 8 kN to answer the followings 1) Express force in each cable in cartesian coordinate system 2) Calculate moment due to both cables and force 4kN about point A 3) Calculate moment due to both cables and force along line BC B. 5 m T1 Ta 4 kN 5 m 4 m 12 m 5 m -- 4 mConsider the pipe shown in Egur 1). The force F has a magnitude of 800 N and coordinate direction angles of -60.8-120°.7-45. Figure 1 of 1 0.5m 0.4m 03m Part A Determine the moment of force F about point O. Express the result as a Cartesian vector Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures. AE Ivec ? Mo- N-m Submit Request Answer Provide Feedback Next >The moment of the force F-120-lb about the point O in Cartesian vector form is. 4ft Select one: a. Mg = 200- 400k b. Mo =-200 + 400% c. Mo 200j-400%
- HOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5mF1 F2 a F3 A d. F4 E Consider the following values: - a = 11 m; b = 6 m; c = 8 m; d = 3 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 KN; F4 = 20 kN; F5 = 2 kN; F5 a = 30° , 0 = 60° ,B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) -1.2 kN.m b) 12.7 kN.m c) - 4.6 kN.m d) 22.9 kN.m e) - 14.1 kN.m f) 21.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 28.8 kN.m b) 42.7 kN.m c) - 1.6 kN.m d) 10.9 kN.m e) - 1.1 kN.m f) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 63.6 kN.m b) -11.1 kN.m c) 77.4 kN.m d) - 9.1 kN.m e) 24.1 kN.m f) - 85.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 33.6 kN.m b) 83.4 kN.m c) - 1.6 kN.m d) 52.1 kN.m e) 21.1 kN.m f) - 40.1 kN.m 5] What is the moment of the force F2 about point E? a) 80.6 kN.m b) - 8.1 kN.m c) 54.6 kN.m d) 33.1 kN.m e) - 22.1 kN.m f) 28.3 kN.mGiven the Position vector Ř = i+j+3k (m) and the Force vector F = i - 7j + 2k (kN Determine the angle in degrees between the two vectors. Answer:
- The moment of the force F=960-lb about the point O in Cartesian vector form is. F 411 2 ft 4 ft Select one Ma 1000, - 3200kSample Problem 2/5 Calculate the magnitude of the moment about the base point O of the 600-N force 2 m 40 40° 50 600N 4 m 600 N 77TTTTA: Moment arm of the force In the figure, the dashed line extending from the force vector F is called the line of action of F. The force’s moment arm is the perpendicular distance rm from the pivot point P to the line of action. What is rm, the length of the moment arm of the force F about point P? Express your answer in terms of r and θ. Find the moment M about P due to F. Your answer should correctly express both the magnitude and the sign of M. Express your answer in terms of either rm and F or r, θ, and F. B: As shown (Figure 2), resolve the force vector, F, into radial (parallel to r) and tangential (perpendicular to r) components. Find the magnitude of the radial and tangential components, Fr and Ft. Assume that θis between zero and 90 degrees. Express your answers in terms of F and θ Is the following statement true or false? The moment about point…