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At 1.25 atm and 685 K, what volume of CO2 gas forms from the combustion of 34.28 g of C4H10? 2 C,H1,(g) + 13 O,(g) – 8 CO, (g) + 10 H,O(1) First, calculate the number of moles of CO, formed in this reaction and show the conversions required to solve this problem. 34.28 g C4H10 × mol CC Answer Bank 44.01 g CO2 13 mol O2 1 mol H20 18.02 g H2O 10 mol H2O 1 mol CO2 58.14 g C4H10 1 mol O2 1 mol C4H10 8 mol CO2 32.00 g O2 2 mol C4H10 Then, use the ideal gas law to calculate the volume of CO2 gas formed.

At 1.25 atm and 685 K, what volume of CO2 gas forms from the combustion of 34.28 g of C4H10? 2 C,H1,(g) + 13 O,(g) – 8 CO, (g) + 10 H,O(1) First, calculate the number of moles of CO, formed in this reaction and show the conversions required to solve this problem. 34.28 g C4H10 × mol CC Answer Bank 44.01 g CO2 13 mol O2 1 mol H20 18.02 g H2O 10 mol H2O 1 mol CO2 58.14 g C4H10 1 mol O2 1 mol C4H10 8 mol CO2 32.00 g O2 2 mol C4H10 Then, use the ideal gas law to calculate the volume of CO2 gas formed.

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter8: Gases
Section: Chapter Questions
Problem 156CP
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At 1.25 atm and 685 K, what volume of CO2 gas forms from the combustion of 34.28 g of C4H10? 2C,Но(8) + 13 0,(8) — 8СО,(g) + 10H,0() First, calculate the number of moles of CO, formed in this reaction and show the conversions required to solve this problem. mol CO2 34.28 g CH10х Answer Bank 44.01 g CO2 13 mol O2 1 mol H2O 18.02 g H20 10 mol H2O 1 mol CO2 58.14 g C4H10 1 mol O2 1 mol C4H10 8 mol CO2 32.00 g O2 2 mol C4H10 Then, use the ideal gas law to calculate the volume of CO2 gas formed. L V = II
Transcribed Image Text:At 1.25 atm and 685 K, what volume of CO2 gas forms from the combustion of 34.28 g of C4H10? 2C,Но(8) + 13 0,(8) — 8СО,(g) + 10H,0() First, calculate the number of moles of CO, formed in this reaction and show the conversions required to solve this problem. mol CO2 34.28 g CH10х Answer Bank 44.01 g CO2 13 mol O2 1 mol H2O 18.02 g H20 10 mol H2O 1 mol CO2 58.14 g C4H10 1 mol O2 1 mol C4H10 8 mol CO2 32.00 g O2 2 mol C4H10 Then, use the ideal gas law to calculate the volume of CO2 gas formed. L V = II
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