rewrite the highlighted enhanced for loop as a for loop 1 public class LargestValue extends ConsoleProgram2- {public void run(){int[] values{32, 56, 79, 2, 150, 37};int highestValue = findMax(values);System.out.println("The highest score is}+ highestvalue);public static int findMax(int[] numbers){int maxSoFar = numbers[0];// for each loop to rewrite as for loopfor (int num: numbers){if (num> maxSoFar){- EmaxSoFarnum;return maxSoFar;}5 }

public class LargestValue extends ConsoleProgram{public void run(){int [ ] values = {32, 56, 79, 2,…

Answered: ass Lc void ru nt[] valu

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ass Lc void ru nt[] valu

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Types of Loop

Loops are the elements of programming in which a part of code is repeated a particular number of times. Loop executes the series of statements many times till the conditional statement becomes false.

Loops

Any task which is repeated more than one time is called a loop. Basically, loops can be divided into three types as while, do-while and for loop. There are so many programming languages like C, C++, JAVA, PYTHON, and many more where looping statements can be used for repetitive execution.

While Loop

Loop is a feature in the programming language. It helps us to execute a set of instructions regularly. The block of code executes until some conditions provided within that Loop are true.

Question

rewrite the highlighted enhanced for loop as a for loop

1 public class LargestValue extends ConsoleProgram
2- {
public void run()
{
int[] values
{32, 56, 79, 2, 150, 37};
int highestValue = findMax(values);
System.out.println("The highest score is
}
+ highestvalue);
public static int findMax(int[] numbers)
{
int maxSoFar = numbers[0];
// for each loop to rewrite as for loop
for (int num: numbers)
{
if (num> maxSoFar)
{
- E
maxSoFar
num;
return maxSoFar;
}
5 }

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