AS, x = 35m acceleration in & direction = 0 + ax=0 acceleration in y direction=-g ⇒ ay = -9.8m/s² Also initial velocity was totally in x direction Thus, 2 y = 0xt + 12 ayt? -22m = 2/(-9.80) £² पे चे |t = २.|२९ NOW in x direction, x=ut + 1ax +² x = ut +0 35 = 4(2.128) U = 35 2.12 u = 16.51 m/s Answer 22m jg -35m qª
AS, x = 35m acceleration in & direction = 0 + ax=0 acceleration in y direction=-g ⇒ ay = -9.8m/s² Also initial velocity was totally in x direction Thus, 2 y = 0xt + 12 ayt? -22m = 2/(-9.80) £² पे चे |t = २.|२९ NOW in x direction, x=ut + 1ax +² x = ut +0 35 = 4(2.128) U = 35 2.12 u = 16.51 m/s Answer 22m jg -35m qª
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Transcribed Image Text:AS,
x = 35m
acceleration in x direction = 0
+ ax=0
acceleration in
y
direction=-g
|t = 2.12 s
Now in x direction,
⇒ ay = -9.8m/s²
Also initial velocity was totally in x direction
Thus,
y= oxt+f ayta
-22m =
(-9.80) t
u=
x = ut + 1 9xf²
x = ut + 0
35 = 4(2.128)
35
2.12
u = 16.51 m/s
22m
Answer
£g
PLEASE EXPLAIN THE
SOLUTION PROVIDED
ABOVE
-35m
y
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