An constant electric field, E = (31+ 4j) N/C, goes through a surface with area A = (8f – ók) m 2. (This surface can also be expressed as an area of 10 m2 with the direction of the unit vector ( 0.8Î – 0, 6k). What is the magnitude of the electric flux through this area? A) 24 N x m 2/C B) 48 N x m 2/C (c) 0.24 N × m 2/C D) 0.48 N × m ²/C E

An constant electric field, E = (31+ 4j) N/C, goes through a surface with area A = (8f – ók) m 2. (This surface can also be expressed as an area of 10 m2 with the direction of the unit vector ( 0.8Î – 0, 6k). What is the magnitude of the electric flux through this area? A) 24 N x m 2/C B) 48 N x m 2/C (c) 0.24 N × m 2/C D) 0.48 N × m ²/C E

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

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