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- A new table has been requested to support tracking automated emails sent to customers. Create the table and add data as described below. Tablename: email_log Columns: emailid (numeric), emaildate (datetime), customer# (numeric) Primary key: emailid column, define as an Identity Column Add the following data rows and display resulting rows (if any errors occur, explain why the error is expected) Emaildate = current date, customer# = 1007 Emailid = specify to use the column default value, emaildate = current date, customer# = 1008 Emailid = 25, emaildate = current date, customer# = 1009question 1Create a procedure that accepts a customer id and retrieves the id of the products and quantities that the customer ordered. Use an anonymous to call the procedure and output the result. question 2Create a procedure to insert a row into the product table with appropriate valuesUse an anonymous to call the procedure and output the result. creation codeSQL: Add a table-level PRIMARY KEY constraint to the EMPLOYEE table using the ID column. The constraint should be named at creation. (Which means you'll need to drop the table, then recreate.) Create a PRIMARY KEY constraint on the DEPARTMENT table using the ID column. The constraint should be named at creation. (Which means you'll need to drop the table, then recreate.) Add a foreign key reference on the EMPLOYEE table that will ensure that the employee is not assigned to a nonexistent department. Confirm that the constraints were added by querying USER_CONSTRAINTS. Note the types and names of the constraints and include them in your statement comments. Display the object names and types from the USER_OBJECTS data dictionary view for EMPLOYEE and DEPARTMENT tables. You will want to format the columns for readability. Provide comments that include the new tables and indexes created. Modify the EMPLOYEE table by adding a SALARY column of NUMBER data type, precision 7. Confirm…
- A new table has been requested to support tracking automated emails sent to customers.Create the table and add data as described below Tablename: email_logColumns: emailid (numeric), emaildate (datetime), customer# (numeric)Primary key: emailid column, define as an Identity Column Add the following data rows and display resulting rows (if any errors occur, explain why theerror is expected)A(n) _____ join will select only the rows with matching values in the common attribute(s). outer natural cross fullWEEK 3 ASSIGNMENT This assignment contains two parts. You must complete Part I before moving on to Part II. Part I: Using the table you previously worked on, complete the following exercise: Insert a row into your student table where the last name is "Parker", first name is "Sam" and the ZIP code is "68134". You can determine the values for the remaining columns. Select a row from your student table where the last name equals "Parker". Select a row from your student table where the ZIP code is less than "68134". Select the student first and last name from the student table order by the state column. Part II: Complete the following exercise: Using your student table select all students that have a last name of “Parker” and have a first name that starts with “S”. Order your results by state. Using your student table select all students with ZIP codes between “23164” and “98164”. Using your student table select all students where states are in Florida and New York. Using your…
- A new table has been requested to support tracking automated emails sent to customers. Create the table and add data as described below.• Tablename: email_log• Columns: emailid (numeric), emaildate (datetime), customer# (numeric)• Primary key: emailid column, define as an Identity Column• Add the following data rows and display resulting rows (if any errors occur, explain why the error is expected)1. Emaildate ¼ current date, customer# ¼ 10072. Emailid ¼ specify to use the column default value, emaildate ¼ current date, customer# ¼ 10083. Emailid ¼ 25, emaildate ¼ current date, customer# ¼ 1009 (refer to the tables in the JustLee Books database)._____, also known as RESTRICT, yields values for all rows found in a table that satisfy a given condition. DIFFERENCE SELECT UNION INTERSECTWhat restrictions can you apply when you are creating views?
- MySql Workbench CREATE TABLE students ( id INT PRIMARY KEY, first_name VARCHAR(50), last_name VARCHAR(50), age INT, major VARCHAR(50), faculty VARCHAR(50)); CREATE TABLE location ( id INT PRIMARY KEY, name VARCHAR(50), rooms INT); CREATE TABLE faculty ( id INT PRIMARY KEY, name VARCHAR(50), department_id INT); 1. List last name of all students whose first name is longer than 4 letters in ascending order accordingto the last name. Duplicated rows should be removed from the output.2. Count the total number of rooms in Location.3. Find the number of students in each major.4. Find the number of employees in each department who get no commission or have salary less than5000.5. Find the maximum salary of employees in each department that the employee was hired 15 yearsbefore now. *hint: user TIMESTAMPDIFF(<unit type>,<Date_value 1>,<Date_value 2>), the unitcan be YEAR, MONTH, DAY, HOUR, etc...1. ID Last Name First Name Create the My Employee table with the following fields: Not Null Number(4) Varchar(25) Varchar(25) Varchar(8) Number(9,2) Userid Salary 2. Add the constraint Primary Key (ID) to the table. 3. Insert the following data to the table: ID Last Name First Name Ali 1 2 3 4 5 AlChameri Alanizi Hejazi Turki AlKamel Rayen Decham Mohamed Fahhed 4. Select all the data in the table. Userid raptel bdancs bbiri cnewman aropebur I Salary 795 860 1100 750 1550Guided Table Build: We will be Creating a Table called Student For the 6 following questions, your submission will be the query that shows you’ve created the table conforming to the requirements. Create a Table Named Student. The first column should be named ID, and have a data type of Integer The second column should be named First_Name, and have a data type of varchar(255). The third column should be named Last_Name, and have a data type of varchar(255) The fourth column should be named DOB (short for date of birth), and have a data type of date. The firth column should be named Adv_ID (short for advisor ID), and have a data type of integer.
