A 10 Kg satellite resting is space is subjected to the forces listed below for a period of 5.0 s. F 1 = 50 N; East F2 = 60 N; 450 N of E F3 = 20 N; West (a) Determine the net force on the satellite. (b) Determine the velocity of the satellite 6.0 s after the forces began acting on it . (c) Determine the acceleration of the satellite 6.0 s after the forces began acting on it.
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- Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 14,200 kg. The thrust of its engines is 25,000 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.) (a) Calculate (in m/s2) its magnitude of acceleration in a vertical takeoff from the Moon. (b)Could it lift off from Earth? If not, why not? i.) No, the thrust of the module's engines is less than its weight on Earth. ii.)Yes, the thrust of the module's engines is equal to its weight on Earth. iii.)Yes, the thrust of the module's engines is greater than its weight on Earth. iv.)No, the thrust of the module's engines is equal to its weight on Earth. If it could, calculate (in m/s2) the magnitude of its acceleration. (If not, enter NONE.)The centripetal force of an object of mass m is givenby F(r) =mv^2/r, where v is the speed of rotation and ris the distance from the center of rotation.a. Find the rate of change of centripetal force withrespect to the distance from the center of rotation.b. Find the rate of change of centripetal force of anobject with mass 1000 kilograms, velocity of 13.89m/s, and a distance from the center of rotation of200 meters4) A 200g object falls under gravity from rest through a medium which exerts a frictional drag force of 2v?. a) Find the velocity v(t) and b) what is the terminal velocity?
- An electron 1mass = 9.11 * 10-31 kg2 leaves one end of aTV picture tube with zero initial speed and travels in a straight line tothe accelerating grid, which is 1.80 cm away. It reaches the grid with aspeed of 3.00 * 106 m/s. If the accelerating force is constant, compute(a) the acceleration; (b) the time to reach the grid; and (c) the net force,in newtons. Ignore the gravitational force on the electron.An astronaut’s pack weighs 17.5 N when she is on the earth butonly 3.24 N when she is at the surface of a moon. What is the acceleration due to gravity on this moon?An object of mass 10 kg is roleased from rest 4000 m above the ground and allowed to fall under the influence of gravity Assuming the force duo to air resistance is proportional to tho velocity of the object with proportionality constant b 50 N.sec/m, determine the equation of motion of the object When will the object striko the ground? Assume that the accoloration due to gravity is 9.81 m/sec and let x(t) represent the distance the objoct has fallon in 1 seconds Delermine the oquation of motion of the object
- A 12 kg meteor experiences an acceleration of 7.2 m/s*2, when falling towards the earth. a) How high above the earth's surface is the meteor? b) What force will a 30 kg meteor experience at the same altitude?Rectilinear Motion A 75 kg man stands on a spring scale in an elevator. During the first 3 secs of motion from rest, the tension T in the hoisting cable is 8300N. Find the reading R of the scale in N during this interval and the upward velocity v of the elevator at the end of the 3secs. The total mass of the elevator, man, and scale is 750kg. Ans. 830 N & 3.77m/s 2. T = 8300 N 1+ 750(9.81)=7360 N R 75(9.81)= 736 NA block of mass 2.0 kg is placed on a smooth plane, inclined to the horizontal at an angle of 15o. The force of gravity acting on the block is 20 N. What is the acceleration of the block down the plane? How far up the plane was the block released if if took 1.5 s to reach the bottom after it was released from rest?
- An astronaut’s pack weighs 17.5 N when she is on the earth but only 3.24 N when she is at the surface of a moon. (a) What is the acceleration due to gravity on this moon? (b) What is the mass of the pack on this moon?Calculate the force (in N) a 68.0 kg high jumper must exert on the ground to produce an upward acceleration 4.45 times the acceleration due to gravity. (Enter the magnitude.)(a) If you ride in an elevator moving upward with constant speed, is your apparent weight greater than, less than, or equalto your actual weight, mg? (b) Which of the following is the best explanation for your prediction?I. The elevator is moving upward. This will cause a person to press down harder on the floor, giving an apparent weightgreater than mg.II. The elevator moves with zero acceleration, and therefore the apparent weight is equal to mg.III. Because the elevator is moving upward it is partially lifting the person, resulting in an apparent weight less than mg