< >AAprod03-cnow-owl.cengagenow.com+LearningLearningLoginCh 17 Buffers and solubilityLearning× Online tea...y dr. marlow...Member L...[Review Topics][References]1. Buffers: Calculate pH, Acidic (100K ..2 ptM2. Buffers: Calculate pH (Henderson-... 2 ptM3. Buffer Preparation: Direct Additio... 2 pt 1 reqQuestionQuestionUse the References to access important valuesif needed for this question.How many grams of solid sodiumhypochlorite should be added to 0.500L of a 0.242 M hypochlorous acidsolution to prepare a buffer with a pHof 6.497? (K (HCIO) = 3.50 × 10−8)Mass =gQuestion4. Titration Curve: Weak Acid/Strong ... 2 ptM5. Titration Curve: Interpret, Choos... 2 pt 1reqM6. Writing Ksp Expressions2 ptSubmit AnswerRetry Entire Group

From the problem, we have VHClO=0.500LMHClO=0.242M pH is 6.497 Using the pH value, the [H+]…

Answered: < > AA prod03-cnow-owl.cengagenow.com +…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.17QAP

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A diprotic acid, H2B(MM=126g/moL), is determined to be a hydrate, H2B xH2O. A 10.00-g sample of this hydrate is dissolved in enough water to make 150.0 mL of solution. Twenty-five milliliters of this solution requires 48.5 mL of 0.425 M NaOH to reach the equivalence point. What is x?
. How is the strength of an acid related to the fact that a competition for protons exists in aqueous solution between water molecules and the anion of the acid?
A solution is made by dissolving 15.0 g sodium hydroxide in approximately 450 mL water. The solution becomes quite warm, but after it is allowed to return to room temperature, water is added to bring the volume to 500.0 mL of solution. (a) Calculate the pH and pOH in the final solution. (b) Why would we wait for it to return to room temperature? (c) If the mass of the water used to initially dissolve the sodium hydroxide were exactly 450 g and the temperature of the water increased by 8.865 C, how much heat was given off by the dissolution of 15.0 g of solute? Assume the specific heat of the solution is 4.184 J/g. K. What is the molar heat change for the dissolution of sodium hydroxide (known as the enthalpy of solution, Hsol)?
9:44 AM Fri Nov 27 令24% AA A sjc.cengagenow.com + E Football Latest Line... F5 Dynamic... Group Resea... Mastery 10-15 OWLV2 | Onli... C Search Text... C dept.cld G SIERRA SIERRA Module 10-12 [Review Topics] [References] 1. Buffer Solutions: Identify Buffer 2 pts M Use the References to access important values if needed for this question. A buffer solution is made that is 0.341 M in H2S and 0.341 M in 2. Buffer Solutions: Write Equation ... 2 pts 2req Question KHS. Question If Question Kal for H2S is 1.00 x 10-, what is the pH of the buffer solution? 3. Buffer Solutions: Buffer Capacity... 2 pts 2req pH Write the net ionic equation for the reaction that occurs when 0.095 mol HBr is added to 1.00 L of the buffer solution. (Use the lowest ble coefficients. Omit states of matter. Use H3 O* instead of Ht) + Submit Answer Retry Entire Group 8 more group attempts remaining Progress: 1/3 groups Due Nov 28 at 11:55 PM Previous Next Finish Assignment Save and Exit
6:07 LTE 74 Ch 17 Buffers and solubility 1. Buffers: C... 2. Buffers: C... M 3. Buffer P... 1req 4. Titration C... M 1req 5. Titration... Preparation Question [Review Topics] The following graph shows the pH curve for the titration of 25 mL of a 0.1 M monoprotic acid solution with a 0.1 M solution of a monoprotic base. Question Question 6. Writing Ksp... 7. Ksp: Calcul... 6 M 4 8 2 0 M M 8. Common I... 5 10 15 20 25 30 35 40 45 50 mL of 0.1 M base added 9. Precipit... 1req (1) The pH curve M 10. Buffer + represents the titration of a with a ✰ acid Progress: 7/10 groups Due Apr 12 at 10:00 PM base. (2) Choose a Previous Next Finish Assignment Email Instructor Save and Exit Αν 03-cnow-owl.cengagenow.com ?
Some K2SO3 and KHSO, are dissolved in 250.0 mL of solution and the resulting pH is 6.88. Which is greater in this buffer solution, the concentration of So, or the concentration of HSO3-? K.(HSO3-) = 1.0 x 10-7 Oconcentration of SO3²- Oconcentration of HSO3 Oboth are equal If (so.] HSO,. = 0.80 M in this solution, calculate the concentration of [HSO,-] =
O d. an increase in total pressure by the addition of helium gas (constant temper O e. a decrease in the total pressure by increasing the volume of the container (ar Which of the following pairs of substances can be used to make a buffer solution? a. NH3 & NAC3H5COO O b. NHal & C2H5COOH O C HF & HCIO O d. HBr & LIOH Oe. CH;COOH & KOH C H
atistics (22111--AB---C.. [References) Given a 1.00 L solution that is 0.60 M HF and 1.00 M KF, calculate the pH after 0.10 mol NaOH is added, and calculate the pH after 0.22 mol HCl is added to the original solution. Ka = 7.2x10-4 pH = when NaOH is added pH = when HCl is added
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G. How would you make 350mL of a buffer with a total concentration of 0.75M and a pH of 9.00 from the list of materials below? (your answer should include the volumes of two solutions and the amount of DI water needed to reach the total volume) [remember: vol* total conc->total moles->moles weak, targetpH->ratio->stoich->moles strong] i. A solution of 1.25 M hydrochloric acid ii. A solution of 1.25 M sodium hydroxide iii. A solution of 1.25 M chloroacetic acid (pKa = 2.85) iv. A solution of 1.25 M ammonia (pka = 9.25) v. A solution of 1.25 M carbonic acid (pKa1 = 6.37, pka2 = 10.32 vi. A solution of 1.25 M acetic acid (pka = 4.75) Dilution 1) What would be the volume of weak component and what would be the volume of strong component? Polyprati Chem 129 Topic Set 7 Variations of titration and Buffers Weak MV MV (0.75) (850) = 1.25 (x) pk 2) What would be the capacity of the buffer? behavior x = 210 mL 3) After the buffer is made, what would the pH change to if 24.5mL of 1.25 M…
Write the reaction that occurs and calculate the pH after... 15.0 mL of 0.100 M NaOH is added to 5.00 mL of 0.150 M HCl 25.0mLof0.10MNaOHisaddedto40.0mLof0.20MHF. (Ka 3.5x10-4) 80.0mLof0.10MNaOHisaddedto40.0mLof0.20MHF. (Ka 3.5x10-4)

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