A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine angle of friction Hint: Draw the Mohr Circle a.19 b.45.5 c.43 d.54.5

A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine angle of friction Hint: Draw the Mohr Circle a.19 b.45.5 c.43 d.54.5

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter6: Vertical Stress Increase In Soil

Section: Chapter Questions

Problem 6.12P: Refer to Problem 6.1. Using Eqs. (6.3) and (6.29), estimate the average stress increase (Δσav) below...

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A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine angle of friction. Draw the Mohr Circle
A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine the cohesion of soil Hint: Draw the Mohr Circle. a.45.5 b.19 c.43 d.54.5
A cylindrical sample of saturated clay 4 cm in diameter and 8 cm high was tested in an unconfined compression apparatus. Find the unconfined compression strength, if the specimen failed at an axial load of 360 N, when the axial deformation was 8 mm. Find the major stress in kPa if the angle made by the failure plane with the horizontal plane was recorded as 50°. a. 258 b. 210 c. 312 d. 106
Refer to Problem 6.1. Using Eqs. (6.3) and (6.29), estimate the average stress increase (Δσav) below the center of the loaded area between depths of 3 m and 6 m. 6.1 A flexible circular area is subjected to a uniformly distributed load of 150kN/m2 (Figure 6.2). The diameter of the load area is 2 m. Determine the stress increase in a soil mass at points located 3 m below the loaded area at r = 0. 0.4 m, 0.8 m, and 1 m. Use Boussinesq’s solution. Figure 6.2 Increase in pressure under a uniformly loaded flexible circular area
Situation 3- A saturated specimen of cohesionless sand was tested under drained conditions in a triaxial compression test apparatus and the sample failed at a deviator stress of 420 kN/m² and the plane of failure made an angle of 62° with the horizontal. Find the magnitudes of the principal stresses. 19. Calculate the magnitude of the minor principal stress, in kPa. A. 269 C. 131.1 B. 210 D. 165.5 20. Calculate the magnitude of the major principal stress, in kPa. A. 630 C. 551.1 B. 689 D. 585.5 21. What would be the magnitude of the major principal stress (in kPa) at failure for another identical specimen of sand if it is tested under a cell pressure of 180 kN/m²? A. 461 C. 540 B. 636.7 D. 756.7
A cylindrical sample of saturated clay 4 cm in diameter and 8 cm high was tested in an unconfined compression apparatus. Find the unconfined compression strength, if the specimen failed at an axial load of 360 N, when the axial deformation was 8 mm. Find the cohesion in kPa if the angle made by the failure plane with the horizontal plane was recorded as 50°. Include free body diagram. a.312 b.106 c.258 d.210
The angle of internal friction of a cohesive soil which was tested using a tri-axial shear apparatus is equal to 26.57°. Failure occurred when the shearing stress is 250 kPa and the normal stress is 480 kPa. Determine the maximum principal stress at failure, in kPa. Round off to two decimal places. (ANS: 884.55)
A saturated specimen of cohesionless sand was tested under drained conditions in a triaxial compression test apparatus and the sample failed at a deviator stress of 482 kN/m2 and the plane of failure made an angle of 60° with the horizontal. Find the magnitude of the principal minor stress in kPa at failure for identical specimen of sand if it is tested under a cell pressure of 200 kPa. a.600 b.241 c.723 d.200
In a tri-axial test for a normally consolidated soil, the deviator stress is equal to 700 kPa and the angle of failure plane makes with the major principal plane is equal to 60 degrees. Determine the shearing stress at the failure plane. a. 285.57 kPa b. 327.15 kPa c. 346.12 kPa d. 303.11 kPa
SITUATION 14: After conducting a tri-axial test on a sand sample, the normal and shearing stresses on the failure plane at failure were found to be 400 kPa and 350 kPa respectively.48. Which of the following gives the angle of shearing resistance? a. 38.79 b. 41.19 c. 48.81 d. 53.949. Which of the following most nearly gives the angle of failure plane measured from the major principal plane?a. 69.41 b. 64.40 c. 71.99 d. 65.5950. Which of the following most nearly gives the major principal stress? a. 1331.51 Kpa b. 1414.58 Kpa c. 1130.37 Kpa d. 1171.32 Kp
Problem-(5) In a triaxial compression test, the major principal stress was 90 kPa and the minor principal stress was 30 kPa, at failure. The pore pressure at failure was observed to be 10kPa. Find the tangent of the angle of shearing resistance of the sandy soil.
The equation of the effective stress failure envelope for a loose sandy soil was obtained from a direct shear test as Ss = Sn tan 36 degrees; where Ss is shearing stress, Sn is normal stress. A drained triaxial test was conducted with the same soil at a chamber confining pressure of 15 lb/in^2.1. Estimate the angle that the failure plane makes with the major principal plane. a. 63 degreesb. 54 degressc. 45 degreesd. 36 degrees2. Determine the normal stress on the plane that makes an angle of 25 degrees with the major principal plane. a. 61.24 lb/in^2b. 50.14 lb/in^2c. 13.15 lb/in^2d. 16.39 lb/in^23. Determine the shear stress (when the specimen failed) on the plane that makes an angle of 25 degrees with the major principal plane.a. 61.24 lb/in^2b. 50.14 lb/in^2c. 13.15 lb/in^2d. 16.39 lb/in^2