A polynomial f(x) and one or more of its zeros are given. Write all numbers as integers or simplified fractions (a) Find all the zeros. (b) Factor f(x) as a product of linear factors. (c) Solve the equation f(x) = 0. f(x)=6x-17x²+22x-10; 1+i is a zero Part: 0/6 Part 1 of 6 (a) Find all the zeros. f(x) is a third-degree polynomial, so we expect to find three zeros (including multiplicities). Further, note that because f(x) has real coefficients and because 1+i is a zero, then the conjugate must also be a zero. This leaves only one remaining zero to find. Part: 1/6 Part 2 of 6 One strategy is to use synthetic division twice using the two known zeros. Divide by [x-(1-1)]. Using synthetic division, we have Part: 2/6 Part 3 of 6 1-i 6 -17 22 6-6i -17+5i 6 -11-6i 5+ i coefficients of the quotient -10 Since 1+i is a z zero of f(x), it must also be a zero of the quotient. Divide the quotient by [x-(1+i)]. G i X