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A method of analysis yields masses of gold that are low by 0.5 mg. This method is used for analysis of ores that assay about 3.9% gold. What minimum sample mass should be taken if the relative error resulting from a 0.5-mg loss is not to exceed a. -0.1%? Mass= b. -0.4%? Mass= C. -0.8%? Mass= d. -1.1%? Mass= 9 9 6 9

A method of analysis yields masses of gold that are low by 0.5 mg. This method is used for analysis of ores that assay about 3.9% gold. What minimum sample mass should be taken if the relative error resulting from a 0.5-mg loss is not to exceed a. -0.1%? Mass= b. -0.4%? Mass= C. -0.8%? Mass= d. -1.1%? Mass= 9 9 6 9

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter18: Nuclear Reactions
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A method of analysis yields masses of gold that are low by 0.5 mg. This method is used for analysis of ores that assay about 3.9% gold. What minimum sample mass should be taken if the relative error resulting from a 0.5-mg loss is not to exceed a. -0.1%? Mass= b. -0.4%? Mass = C. -0.8%? Mass= d. -1.1%? Mass= g g g 6
Transcribed Image Text:A method of analysis yields masses of gold that are low by 0.5 mg. This method is used for analysis of ores that assay about 3.9% gold. What minimum sample mass should be taken if the relative error resulting from a 0.5-mg loss is not to exceed a. -0.1%? Mass= b. -0.4%? Mass = C. -0.8%? Mass= d. -1.1%? Mass= g g g 6
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