A marketing firm is doing research for an Internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per month on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 1818-2424 years and 2525-3030 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on Internet purchases by people in the 1818-2424 age bracket and Population 2 be the amount of money spent per month on Internet purchases by people in the 2525-3030 age bracket. Assume that the population variances are not the same. Internet Spending per Month 1818-2424 Years 2525-3030 Years Mean Amount Spent 65.5765.57 60.1260.12 Standard Deviation 21.6821.68 15.5215.52 Sample Size 1919 1818 Step 1 of 2 : Construct a 90%90% confidence interval for the true difference between the mean amounts of money per month that people in these two age groups spend on Internet purchases. Round the endpoints of the interval to two decimal places, if necessary.
A marketing firm is doing research for an Internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per month on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 1818-2424 years and 2525-3030 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on Internet purchases by people in the 1818-2424 age bracket and Population 2 be the amount of money spent per month on Internet purchases by people in the 2525-3030 age bracket. Assume that the population variances are not the same. Internet Spending per Month 1818-2424 Years 2525-3030 Years Mean Amount Spent 65.5765.57 60.1260.12 Standard Deviation 21.6821.68 15.5215.52 Sample Size 1919 1818 Step 1 of 2 : Construct a 90%90% confidence interval for the true difference between the mean amounts of money per month that people in these two age groups spend on Internet purchases. Round the endpoints of the interval to two decimal places, if necessary.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 4BGP
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A marketing firm is doing research for an Internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per month on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 1818-2424 years and 2525-3030 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on Internet purchases by people in the 1818-2424 age bracket and Population 2 be the amount of money spent per month on Internet purchases by people in the 2525-3030 age bracket. Assume that the population variances are not the same.
Internet Spending per Month
| 1818-2424 Years | 2525-3030 Years | |
|---|---|---|
| Mean Amount Spent | 65.5765.57 | 60.1260.12 |
| Standard Deviation | 21.6821.68 | 15.5215.52 |
| 1919 | 1818 |
Step 1 of 2 :
Construct a 90%90% confidence interval for the true difference between the mean amounts of money per month that people in these two age groups spend on Internet purchases. Round the endpoints of the interval to two decimal places, if necessary.
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