A light fixture of negligible mass, has three applied forces acting on it as shown. F,| = 4 kN %D 1.2 m 1.2 m 1.2 m 2.8 m |F,| = 6 kN 45 |F,| = 5 kN %3D Using the coordinate system shown, determine the reactive moment necessary for equilibrium about the point 0. MR = Mxi + MyJ + M,k (Answer in Kilo Newton meters) Mx Choose... + My Choose... + Mz Choose... +

A light fixture of negligible mass, has three applied forces acting on it as shown. F,| = 4 kN %D 1.2 m 1.2 m 1.2 m 2.8 m |F,| = 6 kN 45 |F,| = 5 kN %3D Using the coordinate system shown, determine the reactive moment necessary for equilibrium about the point 0. MR = Mxi + MyJ + M,k (Answer in Kilo Newton meters) Mx Choose... + My Choose... + Mz Choose... +

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A light fixture of negligible mass, has three applied forces acting on it as shown. |F.| = 4 kN %D 1.2 m 1.2 m 1.2 m 2.8 m |F,| = 6 kN %3D 45 |F| = 5 kN %3D Using the coordinate system shown, determine the moment created by the Force F2 about the point 0. M2 = Mxi + M,J + M,k (Answer in Kilo Newton meters) My Choose.. + Mz Choose... + Mx Choose...
An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=24.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive to the right. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf to the right, then the other forces in the x-direction must be pointing to the left (-100 lbf) to put the eye bolt in equilibrium. Eye bolt 2steel 3 plate Nut t Wonsher
An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 Ibf with 0 = 30 degrees and p=44 degrees. If the eye bolt is in equilibrium, what is the y-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up %3D the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The y-direction is positive going up. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf going up, then the other forces in the y-direction must be pointing to the down (-100 lbf) to put the eye bolt in equilibrium. Eye bolt steel plate Nut & Washer esc DOO D00 F4 F3 AA %24 F10
F, 70° 30 150 kN F1 The parts are connected by pins at point O. Find the magnitudes of forces F1 and F2 that bring them into equilibrium by 0 : 60°. The parts are connected by pins at point O. O Find the magnitude of the force F1 and the angle = in equilibrium, given that F2 = 80 N. F3 540 ニ %3D Fq The ta ニ

Consider the 100-cm board supporting three loads as shown below. The beam weighs 35 grams. If the system is in equilibrium, a. what is the magnitude of the force exerted by the pin support to the board? b. Find the perpendicular distance, x, of the pin support from the left end of the board. 20 cm C. B 65 g 20 g 10 g A,
A light fixture of negligible mass, has three applied forces acting on it as shown. |F,| = 4 kN 1.2 m 1.2 m 1.2 m 2.8 m |F,| = 6 kN -y 45° |F| = 5 kN %3D Using the coordinate system shown, the number of reactions about point 0 equals Answer:
A light fixture of negligible mass, has three applied forces acting on it as shown. |F,| = 4 kN %3D 1.2 m 1.2 m 1.2 m 2.8 m |F,| = 6 kN y 45° |F;| = 5 kN %3D Using the coordinate system shown, determine the magnitude of the reactive force necessary for equilibrium at point 0. (Answer in Kilo Newton ) Answer:
The x-components of three vectors are Fx, +350 lbf, and -118 lbf. If they are in equilibrium, what is Fx.
F2 a =4 m, b = 2 m and c=8 m %3D !! A force F is required to bring the equilibrium of forces of magnitudes F =550 N. F2=500 N and F = 800 N. %3D %3D Analyse the 3-D representation of all forces in the provided system of coordinates (r, y, z) with Origin at A using the right-hand sign convention and Write the rectangular representation of all forces i+ E [N] 7+
Given: A 3500 lb motor and | 3500 lb plate, as shown, are in equilibrium and supported by three cables and d= 4 ft. 10 ft Find: Magnitude of the tension in each of the cables. В 4 ft `3 ft 3 ft 4 ft Plan: 1) Draw a free body diagram of Point A. Let the unknown force magnitudes be FB, Fc, F D . 2) Represent each force in the Cartesian vector form. 3) Apply equilibrium equations to solve for the 3 unknowns.
1b. IF x=2.1m and z=1.8m, determine the j component of the unit vector u_AD. Answer must include 3 places after the decimal point. 1c. If x=2m and z=1.5m, find out the correct equilibrium equation (Newton's 1st law) for the force components along the y axis. T_B is the tension force in cable AB, T_C is the tension force in cable AC, and T_D is the tension in cable AD. 1d.If x=2.1m and z=1.5m, and the mass of the flower por is m=34kg, determine the tension force T_B in cable AB. Answer mus include 1 place after the decimal point and the proper unit. Take g=9.81 m/s^2
An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F,=200 Ibf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=27.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces (reaction force) on the bolt? If you add up the three force vectors, the reaction force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive and to the right. Eye bolt rsteel plate Nut & Washer